SORT在mysql_fetch_array一個特定的值

Question

我有數據具有完整的數據集...

Id | loc |SubLoc |beds 
1  15  5803  1 
2  15  5803  1 
3  16  2813  1 
4  16  2813  2 
5  16  2830  1 
6  20  2020  4 
7  19  2513  3 

我有這個PHP/MySQL的代碼來遍歷它

select id,loc,SubLoc,beds from table where id != 144 AND price > 140000 AND price < 210000 AND category_id=1 

while($rw = mysql_fetch_array($rs2)){} 

現在我想排序$ RW以這種方式

我有三個值

loc=16,SubLoc=2813,beds=1 

我想顯示同樣的結果，但顯示出以這種方式

1- having loc==16 on top then 
2- having SubLoc = 2813 then 
3- having beds = 1 

所有結果，然後結果

這如何可以在PHP中做的休息嗎？

修訂

我想這些ID

3 as it matches 3 parameters 
4 as it matches 2 parameters 
5 as it matches 2 parametrs 
1 as it matches 1 parameter 

等

Answer 1

試一下：

select id,loc,SubLoc,beds from table1 
where loc = 16 or subloc = 2813 or beds =1 
order by 
    case when loc = 16  then 0 
     when subloc = 2813 then 1 
     when beds = 1  then 2 end asc 

DEMO

得到其他結果還沒有匹配然後使用此：

select id,loc,SubLoc,beds from table1 
order by 
    case when loc = 16  then 0 
      when subloc = 2813 then 1 
      when beds = 1  then 2 
      else 3 end asc 

DEMO

編輯：包括所有情況下使用它：

select id,loc,SubLoc,beds from table1 
    order by 
    case when loc = 16 and subloc=2013 and beds = 1 then 0 
     when loc = 16  and subloc = 2813  then 1 
     when loc = 16  and beds = 1   then 2 
     when subloc = 2813 and beds = 1   then 3 
     when loc = 16        then 4 
     when subloc = 2813       then 5 
     when beds = 1        then 6 
     else 7 end asc 

Answer 2

與爲了嘗試

ORDER BY SubLoc=16 DESC,loc, beds