美好的一天! 我正在與我的項目一起工作,需要指出小時是否存在,請假,假期。如果員工在場,我會統計時間。如果需要休假和假期,總工資時間是他們的工作時間表。MySQL病例陳述雙重結果
Select `leave`.emp_id,
leave_request.date,
CASE WHEN leave.status_id = 4 AND leave_request.with_pay = 1 THEN
(
SELECT TIMESTAMPDIFF(HOUR, w_s.time_in, w_s.time_out)
FROM working_schedule w_s
JOIN employee_working_schedule ews ON w_s.id = ews.working_schedule_id
WHERE ews.employee_id = '01-0001'
)
WHEN leave.status_id = 4 AND leave_request.with_pay = 0 THEN '0'
END AS status
FROM `leave`
JOIN leave_request On `leave`.id = leave_request.`leave_id`
JOIN employee_logs AS e_l ON leave.emp_id = e_l.employee_id
WHERE `leave`.emp_id = '01-0001'
UNION
SELECT e.employee_code AS id,
CAST(e_l.time_in As date) day,
CASE WHEN e_l.time_in IS NOT NULL THEN TIMESTAMPDIFF(HOUR, e_l.time_in, e_l.time_out)
FROM employee e
LEFT JOIN employee_logs e_l ON e.employee_code = e_l.employee_id
LEFT JOIN employee_company e_c ON e.employee_code = e_c.employee_id
LEFT JOIN company c ON e_c.company_id = c.id
JOIN employee_working_schedule ews On e.employee_code = ews.employee_id
JOIN working_schedule w_s On ews.working_schedule_id = w_s.id
WHERE e.employee_code = '01-0001'
AND e_l.time_in BETWEEN '2017-09-01' AND '2017-09-28'
UNION
SELECT '01-0001',
CASE WHEN holiday.date BETWEEN '2017-09-01' AND '2017-09-28' THEN
(SELECT holiday.date) END AS date,
CASE WHEN holiday.date BETWEEN '2017-09-01' AND '2017-09-28' THEN
(
SELECT TIMESTAMPDIFF(HOUR, w_s.time_in, w_s.time_out)
FROM working_schedule w_s
JOIN employee_working_schedule ews ON w_s.id = ews.working_schedule_id
WHERE ews.employee_id = '01-0001'
)
END AS status
FROM holiday
所以是有可能在這裏添加其他結果。例如(CASE WHEN e_l.time_in IS NOT NULL THEN TIMESTAMPDIFF(HOUR,e_l.time_in,e_l.time_out)END AS hours_count)THEN
Present
END AS狀態
爲什麼不爲每個select語句添加另一列,例如,第二個select語句添加''Present'As Status' –
因此有可能在案例中添加另一列@VikiTheolorado –