在SQL Server中積累計數

Question

說如果我有一個2列 - ID，金錢的表。 我想做一個查詢，以找出多少ID有錢少於100,200,300，...，10000 我應該如何在SQL Server中做到這一點？我需要使用變量嗎？

Answer 1

有時很簡單，以使用循環中的存儲過程：

CREATE TABLE #tmp0(
bucket int, 
accumulator int, 
) 

/* for(n = maxvalue; n > 0; n -= 100) */ 

Declare @n int 
select @n = (select 100 + (100 * (max(moneyField)/100)) from tbl) 
while @n > 0 
begin 
    insert into #tmp0 (bucket, accumulator) 
     (select @n, count(*) from tbl where moneyField < @n) 
    select @n = @n - 100 
end 
select * from #tmp0 order by bucket 

drop table #tmp0 

Answer 2

假設ID是一個鍵柱，嘗試：

Select Case When money < 100 Then 'LT100' 
      When money < 200 Then 'From100To199' 
      When money < 300 Then 'From200To299' 
      When money < 1000 Then 'From300To999' 
           Else 'GE1000' End Bucket, 
     Count(*) Count 
From Table 
Group By Case When money < 100 Then 'LT100' 
      When money < 200 Then 'From100To199' 
      When money < 300 Then 'From200To299' 
      When money < 1000 Then 'From300To999' 
           Else 'GE1000' End 

編輯： 如果桶的長度或大小是常數，（或可被表示爲一個SQL表達式），則可以做通過定義桶作爲表達式的輸出，如在，例如，以限定每$ 100美元桶的桶中的任何任意數目：

Select Str(Floor(Cast(money/100)), 8, 0) Bucket, 
     Count(*) Count 
From Table 
Group By Str(Floor(Cast(money/100)), 8, 0) 

，或者有100個美元水桶高達1000 $，然後$ 1000從那裏起水桶：

Select Case When Money < 1000 
      Then Str(Floor(Cast(money/100)), 8, 0) 
      Else Str(Floor(Cast(money/1000)), 8, 0) End Bucket, 
     Count(*) Count 
From Table 
Group By Case When Money < 1000 
      Then Str(Floor(Cast(money/100)), 8, 0) 
      Else Str(Floor(Cast(money/1000)), 8, 0) End 

獲得累積計數，我會使用上面的SQL querys的輸出作爲另一個SQL子查詢： 使用第一個爲例：

Select LT100, 
     LT100 + From100To199 LT200, 
     LT100 + From100To199 + From200To299 LT300, 
     LT100 + From100To199 + From200To299 + From300To999 LT1000, 
     LT100 + From100To199 + From200To299 + From300To999 + GE1000 Total  
    From (Select Case When money < 100 Then 'LT100' 
       When money < 200 Then 'From100To199' 
       When money < 300 Then 'From200To299' 
       When money < 1000 Then 'From300To999' 
            Else 'GE1000' End Bucket, 
      Count(*) Count 
     From Table 
     Group By Case When money < 100 Then 'LT100' 
       When money < 200 Then 'From100To199' 
       When money < 300 Then 'From200To299' 
       When money < 1000 Then 'From300To999' 
            Else 'GE1000' End) Z 

Answer 3

SELECT 
    SUM(CASE WHEN MONEY < 100 THEN 1 ELSE 0 END AS '0-100' 
    ,SUM(CASE WHEN MONEY >= 100 AND MONEY < 200 THEN 1 ELSE 0 END AS '100-200' 
    ,SUM(CASE WHEN MONEY >= 200 AND MONEY < 300 THEN 1 ELSE 0 END AS '200-300' 
FROM 
    Table