管對角2

Question

複雜的JSON我有如下一個複雜的JSON：

dashboardMenu:[ 
    { 
     category:'Physical Inventory', 
     subCategory:[ 
     { 
      'subcategory':'Upload PI Count Schedule', 
      'icon':'glyphicon-time', 
      'shortcode':'A1', 
      'router':'/physical-inventory/PIUpload' 
     }, 
     { 
      'subcategory':'Review PI Count Schedule', 
      'icon':'glyphicon-list-alt', 
      'shortcode':'B1', 
      'router':'/physical-inventory/PIReview' 
     }, 
     { 
      'subcategory':'Manage PI Group', 
      'icon':'glyphicon-wrench', 
      'shortcode':'B1', 

     } 
     ] 
    }, 
    { 
     category:'Notification Management', 
     subCategory:[ 
     { 
      'subcategory':'Create Notification', 
      'icon':'glyphicon-envelope', 
      'shortcode':'A1', 
      'router':'/notification-management/createNotification' 
     }, 
     { 
      'subcategory':'Review Notification', 
      'icon':'glyphicon-list-alt', 
      'shortcode':'B1' 
     } 
     ] 

我想補充的管道，將過濾掉類別，子類別的基礎上的數據。 我設法從類別中過濾出數據，但我無法過濾來自子類別的數據。 管 -

if (stringToSearch !== undefined) 

return items 
.filter(item => 
    item.category.toLowerCase().indexOf(stringToSearch) !== -1 || item.category.toLowerCase().indexOf(stringToSearch) !== -1 
); 

Answer 1

如果你正在尋找一種方式來獲得的項目，其中包含子類別的一個嘗試：

return items.filter((item) => { 
    const filtered = item.subCategory.filter((sub) => { 
     return sub.subcategory.toLowerCase().indexOf(stringToSearch) > -1; 
    }); 
    return item.category.toLowerCase().indexOf(stringToSearch) > -1 || filtered.length; 
});