如何記錄在Python中輸入的最高和最低編號？

Question

我不知道什麼是我的錯，這是我現在有多遠了：

x = 1 
e = 0 
while x <= 50: 
    print "Please enter a number (from 1 to 9):" 
    b = float(raw_input()) 
    asd = 0 
    if asd == 0: 
     h = b 
     l = b   
     asd = 1 
    if b < l: 
     l = b 
    elif b > h: 
     h = b 
    if 1 <= b or b <= 9: 
     x = x * b 
     print x 
    else: 
     print "Number is too large or too small." 
    e = e + 1 

print "You have reached a value over 50." 
print "Highest number entered:", h 
print "Lowest number entered:", l 
print "Entered numbers:", e 

這是程序的輸出：

Please enter a number (from 1 to 9): 
5 
5.0 
Please enter a number (from 1 to 9): 
4 
20.0 
Please enter a number (from 1 to 9): 
5 
100.0 
You have reached a value over 50. 
Highest number entered: 5.0 
Lowest number entered: 5.0 
Entered numbers: 3 

爲什麼該程序給我5而不是4作爲輸入的最低數字，我該如何糾正？

Answer 1

每當你經過循環，要設置asd到0，使if聲明它下面執行每一次，所以你總是一味的與用戶剛輸入的值，你已經命名爲更新lb

Answer 2

你不斷進行復位asd每次迭代中，你需要設置外循環的變量，我會用一個列表，這將讓你獲得最小/最大和有效輸入數：

nums = [] # hold all nums outside the loop 
limit = 1 
while 50 >= limit: 
    num = float(raw_input("Please enter a number (from 1 to 9)") 
    if 1 <= num <= 9: 
     limit *= num 
     nums.append(num) # add all to list 
    else: 
     print "Number is too large or too small." 

print "You have reached a value over 50." 
print "Highest number entered:", max(nums) 
print "Lowest number entered:", min(nums) 
print "Entered numbers:", len(nums) 

Answer 3

只是爲了好玩:)

def get_float_input(msg="Enter a Number:"): 
    while True: 
     try: 
      return float(raw_input(msg)) 
     except ValueError: 
      print "Invalid Input Please Enter A Float!" 

from itertools import takewhile 
my_list = sorted(takewhile(lambda val:val < 50,iter(get_float_input,"Y"))) 
print "You Have Entered A # Greater than 50" 
print "Min:",my_list[0] 
print "Max:",my_list[-1] 
print "Entered %d Numbers"%len(my_list)