*和[]中哪一個在C中最強？

Question

可能重複：
C pointer to array/array of pointers disambiguation

在C中，是int *thing[5]五個指針的數組，每個指向的整數，或指向的五個整數數組？

Answer 1

[]王牌*每C precedence table這意味着你有一個五個int指針的數組。

Answer 2

也許是重複的......它是一個由五個指向整數的指針組成的數組;在類似的問題中引用的程序cdecl可以爲新手有用：

cdecl> explain int *t[5]; 
declare t as array 5 of pointer to int 

Answer 3

如有疑問，使用括號 - 維護程序員會感謝你

Answer 4

（如將您在上午05點，當你終於找到了這個錯誤！）

缺席任何顯式的分組與括號，既有數組下標操作者[]和函數調用操作()綁定之前*，所以

T *a[N];  -- a is an N-element array of pointer to T 
T (*a)[N];  -- a is a pointer to an N-element array of T 

T *f();   -- f is a function returning pointer to T 
T (*f)();  -- f is a pointer to a function returning T 

這從語法如下（取。1.從哈比森&斯蒂爾，第5版，附錄B）：

 
declarator: 
    pointer-declarator 
    direct-declarator 

pointer-declarator: 
    pointer direct-declarator 

pointer: 
    * type-qualifier-listopt 
    * type-qualifier-listopt pointer 

direct-declarator: 
    simple-declarator 
    (declarator) 
    function-declarator 
    array-declarator 

function-declarator: 
    direct-declarator (parameter-type-list) 
    direct-declarator (identifier-listopt) 

array-declarator: 
    direct-declarator [ constant-expressionopt ] 
    direct-declarator [ array-qualifier-listopt array-size-expressionopt ]  
    direct-declarator [ array-qualifier-listopt * ]