計算逗號分隔值的用戶數

我在我的數據庫中有逗號分隔的字段base_users。如何查詢以計算該組的totaluser？如果數據不在逗號分隔的字段中，我沒有問題來計算totaluser。計算逗號分隔值的用戶數

SELECT COUNT(base_u_id) AS totaluser 
FROM base_users 
WHERE base_u_group =".$row['base_gp_id']."

 
1)base_users 
|base_u_id | base_u_name | base_u_group | 
------------------------------------------ 
| 1  | username1 | 1, 2, 4 | 
| 2  | username2 | 3   | 
| 3  | username3 | 3, 4  | 
| 4  | username4 | 1, 4  | 

2)base_groups       
| base_gp_id | base_gp_name | 
------------------------------ 
| 1  | group1  | 
| 2  | group2  | 
| 3  | group3  | 
| 4  | group4  | 
| 5  | group5  |

從上面的示例數據庫，我預期的結果將是：

Total User of group1 = 2 
Total User of group2 = 1 
Total User of group3 = 2 
Total User of group4 = 3 
Total User of group5 = 0

這是我到目前爲止已經試過：

<?php 
$getUser = base_executeSQL("SELECT * FROM base_users"); 

while($row_getUser = base_fetch_array($getUser)) 
{ 
    $explodeData = explode(", ",$row_getUser['base_u_group']); 
    foreach($explodeData as $data) 
    { 
     $getUserGroupSQL = base_executeSQL("SELECT COUNT(base_u_id) AS totaluser FROM base_users as user, base_groups as gp WHERE gp.base_gp_id ='".$data."' "); 

     while($UserGroupProfile_row = base_fetch_array($getUserGroupSQL)) 
     if (base_num_rows($getUserGroupSQL)!= 0) 
      $totaluser = $UserGroupProfile_row["totaluser"]; 
     elseif (base_num_rows($getUserGroupSQL)== 0) 
      $totaluser = 0; 
    } 
} 
?>

來源

2015-05-14 Sollo

總僅僅是逗號+ 1（或用逗號字符串的長度和字符串的長度沒有逗號，+ 1之間的差）的數目。現在看到正常化 – Strawberry

更好地修復損壞的分貝設計。它需要規範化 –

@Strawberry我發現[這]（http://stackoverflow.com/questions/7020001/how-to-count-items-in-comma-separated-list-mysql）。你是這個意思嗎？ – Sollo

使用以下邏輯：只要HINT

$group = array(1=>0,2=>0,3=>0,4=>0,5=>0); 
$base_u_group = array('1,2,4','3','3,4','1,4'); 
foreach($base_u_group as $gr) { 
     $split = explode(',', $gr); 
     if (!empty($split)) { 
      foreach($split as $val) { 
      if ($val) { 
       $group[$val] = $group[$val] + 1; 
      } 
      } 
     } 
} 
var_dump($group);

來源

2015-05-14 07:48:52 Prasad

感謝您給我邏輯！最後我想出瞭解決方案。 – Sollo

試試這個：

SELECT COUNT(u.base_u_id), g.base_gp_name FROM base_users u 
INNER JOIN base_groups g ON IF(POSITION(',' IN u.base_u_group) > 0, u.base_u_group LIKE ('".$row['base_gp_id'].",%') OR u.base_u_group LIKE ('%, ".$row['base_gp_id'].",%') OR u.base_u_group LIKE ('%, ".$row['base_gp_id']."'), u.base_u_group = '".$row['base_gp_id']."') 
WHERE g.base_gp_id = ".$row['base_gp_id']."

來源

2015-05-14 07:47:51 Serge

這不適合我。它只包含1個用戶。 – Sollo

計算逗號分隔值的用戶數

回答

相關問題