查找字符

Question

我有一個看起來像這樣從XLSX文件中去掉數據：

[6, 2]=>"Comment", [6, 3]=>"Complaint", [6, 4]=>"Enquiry" 

我想搜索的陣列和前括號返回第二個數字的值。即，搜索Complaint應該返回3。任何幫助表示讚賞。

NB - 根據對數組的註釋更新。刪除了OP中的字符串轉換。

require 'roo' 

today_file=(File.dirname(__FILE__) + '/output/today-report.xlsx') 

def by_value(data, value) 
    found = data.find do |k, v| 
    v == value 
    end 

    found and found[0][1] 
end 

data = Roo::Excelx.new (today_file) 

output = by_value(data, "Complaint").inspect 

puts output 

當運行這個返回「零」

從這個陣列的輸出是這種形式：

{[1, 1]=>"YESTERDAY - 02/10/14", [1, 4]=>"Another comment below the fold - scroll down", [2, 1]=>"Yesterday we received 11 regarding the service.", [4, 1]=>"TYPE", [6, 1]=>"", [6, 2]=>"Comment", [6, 3]=>"Complaint", [6, 4]=>"Enquiry", [6, 5]=>"Total (Type)", [7, 1]=>"Editorial and other queries", [7, 2]=>1.0, [7, 3]=>7.0,...} 

Answer 1

這是一個奇怪的要求。這是如何做到這一點。

word = "Complaint" 
data_string[/, (\d+)\]=>"#{Regexp.escape(word)}"/, 1] # => "3" 

Answer 2

如果你是新來的Ruby，你會想花時間熟悉Enumerable庫。它有很多操作和提取數據的工具。

在這種情況下，find這項工作：

def by_value(data, value) 
    # Find the key/value pair where the value matches 
    found = data.find do |k, v| 
    v == value 
    end 

    # If one of these was found, pull the second number from the key 
    found and found[0][1] 
end 

data = {[6, 2]=>"Comment", [6, 3]=>"Complaint", [6, 4]=>"Enquiry"} 

puts by_value(data, "Complaint").inspect 
# => 3 

值得一提的是，這是一個相對緩慢的操作，因爲你正在做一個線性搜索。如果這樣做了足夠頻繁你要反轉它使搜索更快：

def by_value(data, value) 
    found = data[value] 

    found and found[1] 
end 

# Using Hash#invert switches the keys and values so you can now look-up by value 
data = {[6, 2]=>"Comment", [6, 3]=>"Complaint", [6, 4]=>"Enquiry"}.invert 

puts by_value(data, "Complaint").inspect 
# => 3