添加陣列存儲在cookie的陣列

Question

具有存儲一個數組變量作爲cookie，然後加入在單獨的陣列到餅乾已經包含數組

$mysqli = mysqli_connect($db_host,$db_user,$db_pass,$db_base); 
     if (mysqli_connect_errno()) 
     { 
      printf("Connect failed: %s\n", mysqli_connect_error()); 
      exit(); 
     } 
     // Displays a message saying product was added to the basket 
     $message = $_POST['product_name']." was added to the basket"; 
     echo "<script>alert(".$message.")</script>"; 

     // Sets the basket 
     $itemID = $_POST['product_id']; 
     $itemQuantity = $_POST['product_quantity']; 
     if ($itemQuantity > 0) 
     { 
      $items = [$itemID, $itemQuantity]; 

      // Returns cookie value as array 
      $basket_array = (unserialize($_COOKIE['eg_basket'])); 

      // Adds to array into cookie array 
      $basket = serialize(array_push($basket_array, $items)); 

      // Sets basket back as cookie 
      setcookie('eg_basket', $basket); // will expire on browser close 

      // Displays message 
      echo "<h3 style='text-align:center'>".$_POST['product_name']." was added to the basket</h3>"; 
      echo "<br/>"; 
      echo "<p style='text-align:center'>Please click below to return to the previous page</p>"; 
     } 
     else 
     { 
      echo "<h3 style='text-align:center'>ERROR: ".$_POST['product_name']." was not added to the basket, invalid quantity given</h3>"; 
     } 

      echo "<form method='POST' action='product_info.php'><input style='display:none' type='number' name='product_id_POST' value='".$_POST['product_id']."'><input style='text-align:center' type='submit' value='Return'></form>"; 


     // close the connection 
     mysqli_close($mysqli); 
    ?> 

我所tryng做的是創造一個問題將存儲產品ID陣列的cookie;以及數量

例如cookie = [[product_id，quantity]，[product_id，quantity]，.......]; 然而

即時通訊相當肯定這是不是這樣的，但是這是我使用創造了籃下的cookie，如果不存在的話（可能這就是爲什麼cookie將不接受任何新的價值的原因代碼

// Checks is cookie is already set - basket only 
    if (!isSet($_COOKIE['eg_basket'])) 
    { 
     $basket = serialize([]); 
     setcookie('eg_basket', $basket); // will expire on browser close 
    } 

感謝，任何幫助是極大的讚賞

公牛

Answer 1

您不能發送的cookie到瀏覽器時，頭已經被髮送，請參閱the manual。

所以您需要登錄您的消息，而在這裏迴盪什麼：

echo "<script>alert(".$message.")</script>"; 

，並確保您setcookie()行之前沒有其他輸出發送到瀏覽器。