我正在使用Zillow API來獲取搜索結果,並且遇到了麻煩。我使用thier GetSearchResults的工具,我得到的錯誤:獲取API的PHP嘗試獲取非對象的屬性
Trying to get property of non-object
上線,其中i使用->
符號從XML得到的值。我已經閱讀過關於它的討論,也許我正在做記號錯誤,但我沒有看到任何錯誤。我如何從這個對象獲取數據?
這是我目前的代碼。
<?php
$zillow_id = 'X1-ZWz19g3j9ffabv_7galu';
$search = isset($_GET['5411 lydia ave'])?$_GET['5411 lydia ave']:"";
$citystate = isset($_GET['kansascitymo64110'])?$_GET['kansascitymo64110']:"";
$address = urlencode($search);
$citystatezip = urlencode($citystate);
$url = "http://www.zillow.com/webservice/GetSearchResults.htm?zws-id=$zillow_id&address=$address&citystatezip=$citystatezip";
$result = file_get_contents($url);
$data = simplexml_load_string($result);
$zpid=$data->response->results->result[0]->zpid;
echo $zpid;
?>
下面是我講的是XML:在這種情況下
<SearchResults:searchresults xmlns:xsi="http://www.w3.org/2001/XMLSchema- instance" xmlns:SearchResults="http://www.zillow.com/static/xsd/SearchResults.xsd" xsi:schemaLocation="http://www.zillow.com/static/xsd/SearchResults.xsd http://www.zillowstatic.com/vstatic/5b67875/static/xsd/SearchResults.xsd">
<request>...</request>
<message>...</message>
<response>
<results>
<result>
<zpid>2349353</zpid>
<links>...</links>
<address>
<street>5411 Lydia Ave</street>
<zipcode>64110</zipcode>
<city>Kansas City</city>
<state>MO</state>
<latitude>39.02831</latitude>
<longitude>-94.568747</longitude>
</address>
<zestimate>...</zestimate>
<localRealEstate>...</localRealEstate>
</result>
</results>
</response>
</SearchResults:searchresults>