我想在擴展彈出窗口中使用Google開發者AngularJS庫,但出現錯誤。在Chrome瀏覽器擴展中使用AngularJS
Error: Code generation from strings disallowed for this context at Function (unknown source) at Jb (chrome-extension://jambnlbfljcfpomlclcgphfmkjfiphkb/lib/angular.js:74:18) at k (chrome-extension://jambnlbfljcfpomlclcgphfmkjfiphkb/lib/angular.js:62:357) at Jc (chrome-extension://jambnlbfljcfpomlclcgphfmkjfiphkb/lib/angular.js:64:37) at Lc (chrome-extension://jambnlbfljcfpomlclcgphfmkjfiphkb/lib/angular.js:69:166) at chrome-extension://jambnlbfljcfpomlclcgphfmkjfiphkb/lib/angular.js:74:241 at chrome-extension://jambnlbfljcfpomlclcgphfmkjfiphkb/lib/angular.js:51:270 at F (chrome-extension://jambnlbfljcfpomlclcgphfmkjfiphkb/lib/angular.js:47:339) at X (chrome-extension://jambnlbfljcfpomlclcgphfmkjfiphkb/lib/angular.js:39:390) at t (chrome-extension://jambnlbfljcfpomlclcgphfmkjfiphkb/lib/angular.js:38:286)
什麼是寫一個谷歌瀏覽器插件清單文件?:
"content_security_policy": "default-src 'self'; script-src 'unsafe-eval' 'unsafe-inline'; style-src 'unsafe-inline'",
目前它拋出一個錯誤以下content_security_policy指令的正確方法...
這是因爲有問題的文檔是XHTML。 XHTML是XML,而XML不允許沒有值的屬性。 –