使用查詢生成器的Laravel嵌套連接查詢

Question

這是一個搜索函數，它返回每個成員註冊的最近一年。

我知道它與DB :: raw（）調用。但無法讓它與查詢構建器一起工作。

工作代碼：

$query = DB::table('membership as m'); 
$query->join(
    DB::raw(
     '(SELECT my.* 
     FROM membership_years my 
     INNER JOIN (
      SELECT member_id,MAX(membership_year) AS max_my 
      FROM membership_years 
      GROUP BY member_id 
     ) my2 
     ON my.member_id = my2.member_id 
     AND my.membership_year = my2.max_my 
     ) my' 
    ) 
,'m.id','=','my.member_id'); 

我在查詢生成器代碼嘗試：

$query = DB::table('membership as m'); 
$query->join('membership_years as my', 
    function($j1){ 
    $j1->join('membership_years as my2', 
     function($j2){ 
     $j2->where('my.membership_year','=','MAX(my2.membership_year)') 
     ->on('my.member_id','=','my2.member_id'); 
     } 
    )->on('m.id','=','my.member_id'); 
    } 
); 

產生的錯誤是：

調用未定義的方法照亮\數據庫\ Query \ JoinClause :: join（）

我不確定這是否是因爲$j2無法再訪問連接方法？

原MySQL查詢：

SELECT my.membership_year,m.* 
FROM membership AS m 
INNER JOIN 
    (
     SELECT my1.* 
     FROM membership_years my1 
     INNER JOIN 
     (
      SELECT member_id,MAX(membership_year) AS max_my 
      FROM membership_years 
      GROUP BY member_id 
     ) my2 
     ON my1.member_id = my2.member_id 
     AND my1.membership_year = my2.max_my 
    ) my 
ON m.id = my.member_id 
ORDER BY m.id ASC 

Answer 1

方式1.你可以寫與建設者查詢的一部分：

$query = DB::table('membership as m') 
     ->select('my.membership_year', 'm.*') 
     ->join(DB::raw('(
      SELECT my1.* 
      FROM membership_years my1 
      INNER JOIN (
       SELECT member_id, MAX(membership_year) AS max_my 
       FROM membership_years 
       GROUP BY member_id 
      ) my2 
      ON my1.member_id = my2.member_id 
      AND my1.membership_year = my2.max_my 
     ) my'), 
     'm.id', '=', 'my.member_id') 
     ->orderBy('m.id'); 

路2.您也可以編寫子查詢和使用方法toSql()：

$sub1 = DB::table('membership_years') 
    ->select('member_id', DB::raw('MAX(membership_year) AS max_my')) 
    ->groupBy('member_id'); 

$sub2 = DB::table('membership_years as my1') 
    ->select('my1.*') 
    ->join(DB::raw('(' . $sub1->toSql() . ') my2'), 
      function ($join) { 
       $join 
        ->on('my1.member_id', '=', 'my2.member_id') 
        ->on('my1.membership_year', '=', 'my2.max_my'); 
      }); 

$query = DB::table('membership as m') 
    ->select('my.membership_year', 'm.*') 
    ->join(DB::raw('(' . $sub2->toSql() . ') my'), 'm.id', '=', 'my.member_id') 
    ->orderBy('m.id');