NSString containsString崩潰

Question

我想根據其中一個字符串字段來過濾數組。

兩個nameLower和filterLower具有的NSString值內，但我不斷收到：

__NSCFString containsString:]: unrecognized selector sent to instance 0x7f876b79e160 

-(void) filterFriendsArray:(NSString*)filter { 
    [_filteredFriendsArray removeAllObjects]; 
    for (FacebookUser* user in _friendsArray) 
    { 
     NSString* nameLower = [user.user.name lowercaseString]; 
     NSString* filterLower = [filter lowercaseString]; 
     if ([nameLower containsString:filterLower]) 
      [_filteredFriendsArray addObject:user]; 
    } 
    _displayedFriendsArray = _filteredFriendsArray; 
} 

Answer 1

如果你希望你的代碼在iOS 7以及iOS 8的工作，你應該使用rangeOfString的一個電話而不是。基本上如果返回的範圍長度爲零，子字符串不在那裏。

/* These methods return length==0 if the target string is not found. So, to check for containment: ([str rangeOfString:@"target"].length > 0). Note that the length of the range returned by these methods might be different than the length of the target string, due composed characters and such. 
*/ 
- (NSRange)rangeOfString:(NSString *)aString; 
- (NSRange)rangeOfString:(NSString *)aString options:(NSStringCompareOptions)mask; 
- (NSRange)rangeOfString:(NSString *)aString options:(NSStringCompareOptions)mask range:(NSRange)searchRange; 
- (NSRange)rangeOfString:(NSString *)aString options:(NSStringCompareOptions)mask range:(NSRange)searchRange locale:(NSLocale *)locale NS_AVAILABLE(10_5, 2_0); 

顯然，這是微不足道的實施使用rangeOfString containsString自己在一個類別：

@implementation NSString (Contains) 

- (BOOL)myContainsString:(NSString*)other { 
    NSRange range = [self rangeOfString:other]; 
    return range.length != 0; 
} 

@end 

Answer 2

比較與NSNotFound rangeOfString

NSRange range = [self rangeOfString:other]; 
if(range.location != NSNotFound){ 
    //do something 
} 

Answer 3

由w0mbat給出的答案斯威夫特版本：

extension NSString { 
    func compatibleContainsString(string: NSString) -> Bool{ 
     let range = self.rangeOfString(string as String) 
     return range.length != 0 
    } 
} 

Answer 4

使用下列內容：

if (![[NSString class] respondsToSelector:@selector(containsString)]) 
    { 
     //ios 7 
     NSRange range = [mystring rangeOfString:other]; 
     if(range.location != NSNotFound){ 
      //do something 
     } 
    } 
    else //for iOS 8 
    { 
      if ([mystring containsString: other]) 
      { 
       //do something 
      }        
    } 

Answer 5

對於那些誰在XLForm遇到這種情況，請確保安裝設備時XLForm使用豆莢

platform :ios, '7' 
pod 'XLForm' 

它已經固定在3.1

從

if ([cellClassString contains:@"/"]) { 

} 

到

if ([cellClassString rangeOfString:@"/"].location != NSNotFound) { 

} 

Answer 6

我概括了我在YJKit解決方案，您可以打電話 - [的NSString containsString：即使對於老版本，下面的iOS 8

bool _yj_streq(const char *str1, const char *str2, size_t length) { 
    for (int i = 0; i < length; i++) { 
     if (*str1++ != *str2++) { 
      return false; 
     } 
    } 
    return true; 
} 

- (BOOL)yj_containsString:(NSString *)string { 

    NSAssert(string != nil, @"*** -[%@ containsString:] can not use nil argument.", [self class]); 

    size_t len1 = (size_t)self.length; 
    size_t len2 = (size_t)string.length; 

    if (len1 == 0 || len2 == 0 || len1 < len2) { 
     return NO; 
    } 

    const char *str1 = self.UTF8String; 
    const char *str2 = string.UTF8String; 

    for (size_t i = 0; i <= len1 - len2; i++) { 
     const char *substr1 = str1 + i; 
     if (_yj_streq(substr1, str2, len2)) { 
      return YES; 
     } else { 
      continue; 
     } 
    } 

    return NO; 
} 

這裏我的源代碼： https://github.com/huang-kun/YJKit/blob/master/YJKit/Base/Foundation/Categories/Generics/NSString%2BYJCompatible.m