我已經搜遍了許多類似的問題,但我無法找到我正在尋找的答案。我很自學,所以我對這個問題表示歉意。基本上我試圖訪問我的數組中的字符串ID並將其轉換爲可讀的字符串,以便我可以將其發送到谷歌地圖,以便用戶可以在那裏導航。這是我得到的最接近的。如何將ArrayList中的int String id轉換爲可用的字符串?
import android.content.Intent;
import android.net.Uri;
import android.os.Bundle;
import android.support.v4.app.Fragment;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.widget.AdapterView;
import android.widget.ListView;
import java.util.ArrayList;
public class FoodFragment extends Fragment {
public FoodFragment() {
}
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
View rootView = inflater.inflate(R.layout.word_list, container, false);
final ArrayList<Location> places = new ArrayList<>();
places.add(new Location(R.string.food1, R.string.desc1, R.drawable.tapass));
places.add(new Location(R.string.food2, R.string.desc2, R.drawable.baguette));
places.add(new Location(R.string.food3, R.string.desc3, R.drawable.sushi));
places.add(new Location(R.string.food4, R.string.desc4, R.drawable.burger));
places.add(new Location(R.string.food5, R.string.desc5, R.drawable.meat));
places.add(new Location(R.string.food6, R.string.desc6, R.drawable.pizza));
final Location here = places.get(0);
final int address = here.getName();
MyAdapter adapter = new MyAdapter(getActivity(), places);
final ListView listView = (ListView) rootView.findViewById(R.id.list);
listView.setAdapter(adapter);
listView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> adapterView, View view, int position, long l) {
Intent intent = new Intent(android.content.Intent.ACTION_VIEW,
Uri.parse("google.navigation:q=" + address));
startActivity(intent);
}
});
return rootView;
}
}
getName來自我的Location類。我意識到它返回一個int(以便我可以將string.xml中的字符串id放入數組中),但是如何獲取它以返回實際的字符串值?
public class Location {
private int mName;
private int mDescription;
private int mImage;
public Location (int name, int description, int image){
mName = name;
mDescription = description;
mImage = image;
}
public int getName(){
return mName;
}
public int getDescription(){
return mDescription;
}
public int getImage(){
return mImage;
}
}
我再次道歉noob問題和任何幫助,非常感謝。
這正是我所尋找的非常感謝你。我太新了+1,但當我有足夠的代表時,我會回來。 –