如何爲下列命令行形成PHP curl請求？

Question

有人可以幫助我在PHP中形成這個通訊請求嗎？

$ curl -u [USER:PASSWORD] https://subs.pinpayments.com/api/v4/meresheep/subscribers/7388.xml

我曾嘗試以下，並獲得唯一的 '假' 返回......

// Query the user to pin payments for the details... 
$curl_url = "https://subs.pinpayments.com/api/v4/xyz-site/subscribers/32.xml"; 

//open connection 
$ch = curl_init(); 

//set the url, number of POST vars, POST data 
curl_setopt($ch, CURLOPT_URL, $url); 
curl_setopt($ch, CURLOPT_RETURNTRANSFER,1); 
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false); 
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Authorization: -u [USER:PASSWORD]')); 

//execute post 
$result = curl_exec($ch); 
curl_close($ch); 

Answer 1

您需要更改CURLOPT_HTTPHEADER行：

curl_setopt($data, CURLOPT_HTTPHEADER, array(
    'Authorization: Basic ' . base64_encode('username:password') 
));