我有一個字符串,如下所示:爆炸字符串
$str = "am_customers.customer_key,am_customers.add_dt,CONCAT(am_customers.first_name,'',am_customers.last_name) as
name,am_customers.cell_phone,am_customers.crm_phase_key, am_customers.source,am_customers.location_key,am_customers.hub_key,
am_customers.crm_priority,am_customers.update_dt";
我想explod用逗號的字符串。但問題是打開和關閉括號,當我嘗試expload用逗號的字符串,我會得到的結果類似如下
Array
(
[0] => am_customers.customer_key
[1] => am_customers.add_dt
[2] => CONCAT(am_customers.first_name
[3] => ''
[4] => am_customers.last_name) as name
[5] => am_customers.cell_phone
[6] => am_customers.crm_phase_key
[7] => am_customers.source
[8] => am_customers.location_key
[9] => am_customers.hub_key
[10] => am_customers.crm_priority
[11] => am_customers.update_dt
)
但我想要的結果類似如下:
Array
(
[0] => am_customers.customer_key
[1] => am_customers.add_dt
[2] => CONCAT(am_customers.first_name,'',am_customers.last_name) as name
[3] => am_customers.last_name) as name
[4] => am_customers.cell_phone
[5] => am_customers.crm_phase_key
[6] => am_customers.source
[7] => am_customers.location_key
[8] => am_customers.hub_key
[9] => am_customers.crm_priority
[10] => am_customers.update_dt
)
有沒有辦法像我想要的那樣做到這一點?
謝謝。
使preg_split。 – Devon