JavaScript的 - 增加了兒童

Question

的價值我有對象的JavaScript數組，像這樣：

[{ 
    name: "Root 1", 
    countCases: 0, 
    children: [ 
     { 
      name: "Root 1.1", 
      countCases: 3 
     }, 
     { 
      name: "Root 1.2", 
      countCases: 1, 
      children: [ 
       { 
        name: "Root 1.2.1", 
        countCases: 3 
       }, 
       { 
        name: "Root 1.2.2", 
        countCases: 1 
       }, 
       { 
        name: "Root 1.2.3", 
        countCases: 1 
       } 
      ] 
     } 
    ] 
}, 
{ 
    name: "Root 2", 
    countCases: 0, 
    children: [ 
     { 
      name: "Root 2.1", 
      countCases: 3 
     }, 
     { 
      name: "Root 2.2", 
      countCases: 0, 
      children: [ 
       { 
        name: "Root 2.2.1", 
        countCases: 3 
       }, 
       { 
        name: "Root 2.2.2", 
        countCases: 1 
       } 
      ] 
     } 
    ] 
}] 

我想加起來所有嵌套的孩子「countCases」的價值。對於這些值是：

Root 1 - 9 
Root 1.1 - 3 
Root 1.2 - 6 
Root 1.2.1 - 3 
Root 1.2.2 - 1 
Root 1.2.3 - 1 
Root 2 - 7 
Root 2.1 - 3 
Root 2.2 - 4 
Root 2.2.1 - 3 
Root 2.2.2 - 1 

所以每個家長都有他們的「countCases」並添加了他所有孩子的「countCases」。預先感謝您的幫助。

@edit：我想是這樣的，但它不是工作：

function addCountCasesToParentFromChildren(data) 
{ 
    var sumCountCases = 0; 
    $.each(data, function(key, value) { 
     sumCountCases = value.countCases; 
     if (value.children != '') 
     { 
      value.countCases += addCountCasesToParentFromChildren(value.children); 
     } 
    }); 

    return sumCountCases; 
} 

@ EDIT2：好的，我做到了。這是解決方案：

function addCountCasesToParentFromChildren(data) 
{ 
    var sumCountCases = 0; 
    $.each(data, function(key, value) { 
     if (value.children != '') 
     { 
      value.countCases += addCountCasesToParentFromChildren(value.children); 
     } 

     sumCountCases += value.countCases; 
    }); 

    return sumCountCases; 
} 

Answer 1

您可以使用此功能ES6：

function aggregate(data) { 
 
    return (data || []).reduce((acc, obj) => { 
 
    var childAcc = aggregate(obj.children); 
 
    var res = { 
 
     name: obj.name, 
 
     sumCountCases: obj.countCases + childAcc.sum 
 
    }; 
 
    return { 
 
     arr: acc.arr.concat([res], childAcc.arr), 
 
     sum: acc.sum + res.sumCountCases 
 
    }; 
 
    }, {arr: [], sum: 0}); 
 
} 
 

 
// sample data 
 
var data = [{ 
 
    name: "Root 1", 
 
    countCases: 0, 
 
    children: [{ 
 
     name: "Root 1.1", 
 
     countCases: 3 
 
    }, { 
 
     name: "Root 1.2", 
 
     countCases: 1, 
 
     children: [{ 
 
      name: "Root 1.2.1", 
 
      countCases: 3 
 
     }, { 
 
      name: "Root 1.2.2", 
 
      countCases: 1 
 
     }, { 
 
      name: "Root 1.2.3", 
 
      countCases: 1 
 
     }] 
 
    }] 
 
}, 
 
{ 
 
    name: "Root 2", 
 
    countCases: 0, 
 
    children: [{ 
 
     name: "Root 2.1", 
 
     countCases: 3 
 
    }, { 
 
     name: "Root 2.2", 
 
     countCases: 0, 
 
     children: [{ 
 
      name: "Root 2.2.1", 
 
      countCases: 3 
 
     }, { 
 
      name: "Root 2.2.2", 
 
      countCases: 1 
 
     }] 
 
    }] 
 
}]; 
 

 
// convert 
 
var { arr, sum } = aggregate(data, 0); 
 

 
console.log(arr);