1
我試圖建立一個CMS,我可以點擊一個星形圖標,它會改變我的數據庫中的art_featured
值,所以說如果art_featured
值爲0,我點擊我的星形圖標我想將字段的值從0更改爲1.我有它的工作原理,但我不知道如何通過art_featured
的值,通常我只是我的id
在我的span
,但我是已經在使用,因此我可以告訴哪篇文章需要更改,所以我如何獲得art_featured
到我的SQL
語句的值,以便我可以運行if和else語句,然後根據art_featured
的值運行某個SQL
語句,通過數據庫字段ID的運行SQL根據字段值
在此先感謝您的幫助!
TABLE
art_id art_title art_company art_featured
1 lorem 1 lorem ipsum 1 1
2 lorem 2 lorem ipsum 2 0
HTML/PHP
<section class="row">
<?php
$sql_categories = "SELECT art_title, art_company, art_id, art_featured FROM app_articles";
if($result = query($sql_categories)){
$list = array();
while($data = mysqli_fetch_assoc($result)){
array_push($list, $data);
}
foreach($list as $i => $row){
?>
<div class="row">
<div class="column two"><p><?php echo $row['art_title']; ?></p></div>
<div class="column two"><p><?php echo $row['art_company']; ?></p></div>
<div class="column one"><span id="<?php echo $row['art_id']; ?>" class="icon-small star"></span></div>
</div>
<?php
}
}
else {
echo "FAIL";
}
?>
</section>
jQuery的
$(".star").click(function(){
var art_id = $(this).attr('id');
$.ajax({
type: "POST",
data: {art_id:art_id},
url: "ajax-feature.php",
success: function(data){
if(data != false) {
}
else {
}
}
});
});
的MySQL/PHP
if(isset($_POST['art_id'])) {
$sql_articles = "UPDATE `app_articles` SET `art_featured` = 1 WHERE `art_id` =".$_POST['art_id'];
if(query($sql_articles)) {
echo "YES";
}
else {
echo "NO";
}
}
else {
echo "FAIL";
}
對不起,我已經有$(document).ready(function {});我忘了包括這一點。我需要知道的是如何將我的sql結果中的php變量傳遞給我正在更新數據庫的sql語句。 – user2201765 2013-03-26 00:14:08
@ user2201765我更新了它。這是你需要的嗎? – 2013-03-26 00:51:39