listview setItemChecked無法正常工作

Question

我遇到了由合併遊標填充的listview問題。 我在我的應用程序中有一個按鈕來選擇我的列表視圖中的所有條目。按下按鈕時調用的函數如下：

private void selectAllEntries() { 
    int numberOfItemsInList = listView.getCount(); 
    for (int i = 0; i < numberOfItemsInList; i++) { 
     this.listView.setItemChecked(i, true); 
    } 
} 

問題是，並非所有條目最後都會被檢查。確實很奇怪。經過一些測試後，我注意到如果我在mergecursor中有10個條目（5個來自遊標a，5個來自遊標b），那麼如果我只在前5個元素上使用setItemChecked，那麼一切正常（這5個條目會被檢查）。如果我在最後5個元素上再次使用setItemchecked，一切正常（光標b的條目被檢查），但是如果我對兩個遊標的元素使用setItemChecked，那麼獲取檢查的元素的最大數量是光標a中元素的數量（在我們的例子中爲5），偏移量爲（我想設置的項目數 - 光標a中的項目數）。我會寫下幾個例子，因爲這是一個非常奇怪的行爲。

Example 1: 
element 0 (from cursor a, unchecked) 
element 1 (from cursor a, unchecked) 
element 2 (from cursor a, unchecked) 
element 3 (from cursor a, unchecked) 
element 4 (from cursor a, unchecked) 
element 5 (from cursor b, unchecked) 
element 6 (from cursor b, unchecked) 
element 7 (from cursor b, unchecked) 
element 8 (from cursor b, unchecked) 
element 9 (from cursor b, unchecked) 

setItemChecked(0,true); 
setItemChecked(1,true); 
setItemChecked(2,true); 
setItemChecked(3,true); 
setItemChecked(4,true); 

Results: 

element 0 (from cursor a, checked) 
element 1 (from cursor a, checked) 
element 2 (from cursor a, checked) 
element 3 (from cursor a, checked) 
element 4 (from cursor a, checked) 
element 5 (from cursor b, unchecked) 
element 6 (from cursor b, unchecked) 
element 7 (from cursor b, unchecked) 
element 8 (from cursor b, unchecked) 
element 9 (from cursor b, unchecked) 

Example 2: 
element 0 (from cursor a, unchecked) 
element 1 (from cursor a, unchecked) 
element 2 (from cursor a, unchecked) 
element 3 (from cursor a, unchecked) 
element 4 (from cursor a, unchecked) 
element 5 (from cursor b, unchecked) 
element 6 (from cursor b, unchecked) 
element 7 (from cursor b, unchecked) 
element 8 (from cursor b, unchecked) 
element 9 (from cursor b, unchecked) 

setItemChecked(5,true); 
setItemChecked(6,true); 
setItemChecked(7,true); 
setItemChecked(8,true); 
setItemChecked(9,true); 

results: 

element 0 (from cursor a, unchecked) 
element 1 (from cursor a, unchecked) 
element 2 (from cursor a, unchecked) 
element 3 (from cursor a, unchecked) 
element 4 (from cursor a, unchecked) 
element 5 (from cursor b, checked) 
element 6 (from cursor b, checked) 
element 7 (from cursor b, checked) 
element 8 (from cursor b, checked) 
element 9 (from cursor b, checked) 

Example 3: 
element 0 (from cursor a, unchecked) 
element 1 (from cursor a, unchecked) 
element 2 (from cursor a, unchecked) 
element 3 (from cursor a, unchecked) 
element 4 (from cursor a, unchecked) 
element 5 (from cursor b, unchecked) 
element 6 (from cursor b, unchecked) 
element 7 (from cursor b, unchecked) 
element 8 (from cursor b, unchecked) 
element 9 (from cursor b, unchecked) 

setItemChecked(0,true); 
setItemChecked(1,true); 
setItemChecked(2,true); 
setItemChecked(3,true); 
setItemChecked(4,true); 
setItemChecked(5,true); 

results in 

element 0 (from cursor a, unchecked) 
element 1 (from cursor a, checked) 
element 2 (from cursor a, checked) 
element 3 (from cursor a, checked) 
element 4 (from cursor a, checked) 
element 5 (from cursor b, checked) 
element 6 (from cursor b, unchecked) 
element 7 (from cursor b, unchecked) 
element 8 (from cursor b, unchecked) 
element 9 (from cursor b, unchecked) 


Example 4: 
element 0 (from cursor a, unchecked) 
element 1 (from cursor a, unchecked) 
element 2 (from cursor a, unchecked) 
element 3 (from cursor a, unchecked) 
element 4 (from cursor a, unchecked) 
element 5 (from cursor b, unchecked) 
element 6 (from cursor b, unchecked) 
element 7 (from cursor b, unchecked) 
element 8 (from cursor b, unchecked) 
element 9 (from cursor b, unchecked) 

setItemChecked(0,true); 
setItemChecked(1,true); 
setItemChecked(2,true); 
setItemChecked(3,true); 
setItemChecked(4,true); 
setItemChecked(5,true); 
setItemChecked(6,true); 

results: 

element 0 (from cursor a, unchecked) 
element 1 (from cursor a, unchecked) 
element 2 (from cursor a, checked) 
element 3 (from cursor a, checked) 
element 4 (from cursor a, checked) 
element 5 (from cursor b, checked) 
element 6 (from cursor b, checked) 
element 7 (from cursor b, unchecked) 
element 8 (from cursor b, unchecked) 
element 9 (from cursor b, unchecked) 


Example 5: 
element 0 (from cursor a, unchecked) 
element 1 (from cursor a, unchecked) 
element 2 (from cursor a, unchecked) 
element 3 (from cursor a, unchecked) 
element 4 (from cursor a, unchecked) 
element 5 (from cursor b, unchecked) 
element 6 (from cursor b, unchecked) 
element 7 (from cursor b, unchecked) 
element 8 (from cursor b, unchecked) 
element 9 (from cursor b, unchecked) 

setItemChecked(0,true); 
setItemChecked(1,true); 
setItemChecked(2,true); 
setItemChecked(3,true); 
setItemChecked(4,true); 
setItemChecked(5,true); 
setItemChecked(6,true); 
setItemChecked(7,true); 

results: 

element 0 (from cursor a, unchecked) 
element 1 (from cursor a, unchecked) 
element 2 (from cursor a, unchecked) 
element 3 (from cursor a, checked) 
element 4 (from cursor a, checked) 
element 5 (from cursor b, checked) 
element 6 (from cursor b, checked) 
element 7 (from cursor b, checked) 
element 8 (from cursor b, unchecked) 
element 9 (from cursor b, unchecked) 

我現在用的是

 listView.setChoiceMode(ListView.CHOICE_MODE_MULTIPLE); 

和

notifyDataSetChanged() 

也沒有幫助。 有什麼幫助嗎？

作爲一個側面說明，

listView.getCount(); 

總是返回視圖

Answer 1

爲alanv說， 條目數正確「的CursorAdapter使用_id列從您的數據庫，以確定行，並且AbsListView使用這個值來跟蹤哪些行被檢查，這聽起來像你的MergeCursor可能會返回重複的ID，例如，遊標A中第一行的_id值與遊標B中第一行的_id相同。那個案子？「

就是這樣。 改變光標後，以提供不同ID的所有工作好 但是：

1. 合併光標是其他光標的串聯，不應該合併光標能夠用相同的ID從不同子來處理遊標（例如通過在內部創建新的ID）。
2. 查看合併遊標的所有結果，並與它們進行交互（點擊它們）工作正常，所以我希望檢查它們以及它是否正常工作？