雖然循環插入三次

Question

我正在構建呼叫評估表，團隊領導評估一個代理給他們打電話的分數。

這裏是我的代碼：

$query = "SELECT uid, section_name, section FROM sections_phase1 WHERE client_uid_fk = '$client'"; 
$sql = mysql_db_query($dbName,$query,$connect);// I'm getting section1,2,3 here 

while ($sec_row = mysql_fetch_assoc($sql)) { 

    ?> 
<tr> 
    <td class="style18"><?php echo $sec_row['section_name']?></td> 
</tr> 
<?php 
$countquestion = 0; 
$query = "SELECT uid, question FROM evaluation_phase1 WHERE client_uid_fk = '$client' AND section = '{$sec_row['section']}'"; 
$result = mysql_db_query($dbName,$query,$connect); 

while ($row = mysql_fetch_assoc($result)) { 
    $countquestion++; 
    ?> 


<tr> 
    <td class="style8"><?php echo $row['question']?><input 
     type="hidden" name="question_id_p1[<?php echo $row['uid']?>]" 
     value="<?php echo $row['uid']?>" /> <input type="hidden" 
     name="section[]" value="<?php echo $sec_row['section']?>" /></td> 
    <td> 
    1<input type="radio" name="answer_p1[<?php echo $row['uid']?>]" value="1" />       
</td> 
    <td> 
    2<input type="radio" name="answer_p1[<?php echo $row['uid']?>]" value="2" /> 
</td> 
    <td> 
    3<input type="radio" name="answer_p1[<?php echo $row['uid']?>]" value="3" /> 
</td> 
    <td> 
    4<input type="radio" name="answer_p1[<?php echo $row['uid']?>]" value="4" /> 
</td> 
    <td> 
    5<input type="radio" name="answer_p1[<?php echo $row['uid']?>]" value="5" /> 
</td> 

    <td> 
    N/A<input type="radio" name="answer_p1[<?php echo $row['uid']?>]" 
     value="0" /> 
</td> 

    <td> 
    <textarea rows="1" cols="15" name="comment_p1[<?php echo $row['uid']?>]"></textarea> 
</td> 
</tr> 
<?php }} 
?> 

提交頁：

$sql_data = array(); 
$sql_prefix = "INSERT INTO agents_phase1(call_info_uid_fk, client_uid_fk, product_uid_fk, team_leaders_uid_fk, agent_uid_fk, question_id, question_answer, section, evaluation_number, comment, time) VALUES"; 
foreach($_POST['answer_p1'] as $id => $answer){ 
    $call_info_id = (int) $_POST['call_id']; 
    $client_id = (int) $_POST['client_id']; 
    $product_id = (int) $_POST['product_id']; 
    $team_leader_id = (int) $_POST['team_leader_id']; 
    $agent_id = (int) $_POST['agent_id']; 
    $question_id = (int) $_POST['question_id_p1'][$id]; 
    $answer  = (int)($answer); 
    $comment  = mysql_real_escape_string ($_POST['comment_p1'][$id]); 
    $used_time = $timeend-$timestart; 
    $section = (int) $_POST['section'][$id]; 

    $sql_data[] = "('$call_info_id', $client_id, $product_id, $team_leader_id, $agent_id, $question_id, '$answer', '$section', '1', '$comment', '$used_time')"; 

    $sql = $sql_prefix.implode(", \n", $sql_data); 
} 
mysql_db_query($dbName, $sql, $connect); 

我的問題是，當我向它添加值數據庫三個時間，它應該只能插入一次。我有一個想法，認爲它與我的時間有關，但似乎無法解決問題。

我真的很感謝一些幫助。

這是輸出，如果我回聲$ SQL：

INSERT INTO agents_phase1(call_info_uid_fk, client_uid_fk, product_uid_fk, team_leaders_uid_fk, agent_uid_fk, question_id, question_answer, section, evaluation_number, comment, time) VALUES('8', 9, 7, 8, 24, 1, '3', '1', '1', '', '704197'), ('8', 9, 7, 8, 24, 2, '4', '1', '1', '', '704197'), ('8', 9, 7, 8, 24, 3, '2', '1', '1', '', '704197'), ('8', 9, 7, 8, 24, 4, '4', '1', '1', '', '704197'), ('8', 9, 7, 8, 24, 5, '2', '1', '1', '', '704197'), ('8', 9, 7, 8, 24, 22, '4', '1', '1', '', '704197'), ('8', 9, 7, 8, 24, 6, '5', '2', '1', '', '704197'), ('8', 9, 7, 8, 24, 7, '3', '2', '1', '', '704197'), ('8', 9, 7, 8, 24, 8, '4', '2', '1', '', '704197'), ('8', 9, 7, 8, 24, 9, '3', '2', '1', '', '704197'), ('8', 9, 7, 8, 24, 10, '4', '2', '1', '', '704197'), ('8', 9, 7, 8, 24, 11, '3', '2', '1', '', '704197'), ('8', 9, 7, 8, 24, 12, '4', '2', '1', '', '704197'), ('8', 9, 7, 8, 24, 13, '3', '2', '1', '', '704197'), ('8', 9, 7, 8, 24, 14, '4', '2', '1', '', '704197'), ('8', 9, 7, 8, 24, 15, '3', '2', '1', '', '704197'), ('8', 9, 7, 8, 24, 16, '4', '2', '1', '', '704197'), ('8', 9, 7, 8, 24, 17, '3', '2', '1', '', '704197'), ('8', 9, 7, 8, 24, 18, '4', '2', '1', '', '704197') 

感謝

Answer 1

一個非常非常糟糕的設計，我必須要說。

我不知道如何插入數據，因爲該sql語句應該會引發錯誤。

至於你的問題，什麼是foreach插入語句？您一次只能發送1個值。每個foreach應該覆蓋變量...

一個大混亂。你應該簡化決策。但不管怎麼說，刪除那個foreach。它應該解決你的問題。

Answer 2

把代碼

$sql = $sql_prefix.implode(", \n", $sql_data); 

foreach循環