我遇到了我的數據問題。 的json看起來像這樣:我該如何在HTML中輸入某些信息形式我的json
[
{
"link": {
"created_at": "2013-10-07T13:31:43+09:00",
"id": 8,
"items_count": 4,
"key": "0iqVSnTU-BtJ1ItVKRe2VMWvRMU",
"mode": "standard",
"name": "sdasadads",
"pusher_key": "1jtsrzl3n6i1DKA3tSZJM6LPnfQ",
"readonly_key": "R_dD5oHMsruu0YzYVKEOA8hKKXA-r",
"updated_at": "2013-10-08T14:06:07+09:00",
"user_id": 2
}
},
{
"link": {
"created_at": "2013-10-07T13:32:56+09:00",
"id": 9,
"items_count": 1,
"key": "Mj-6Cc-_qaGlVTPgqKexzeijYNA",
"mode": "standard",
"name": "Untitled2",
"pusher_key": "hGE0D8TSar_H_Gv9MWdpj26gamM",
"readonly_key": "T53SNKPgyf7KvRUMzDQPaM99AAc-r",
"updated_at": "2013-10-07T13:33:14+09:00",
"user_id": 2
}
},
{
"link": {
"created_at": "2013-10-11T11:18:06+09:00",
"id": 10,
"items_count": 0,
"key": "X_ZoKxFPHtsvSU5W11gXx1653FU",
"mode": "standard",
"name": "Usdadasas",
"pusher_key": "0PZ860awofRKB9XIrXba-xY6u14",
"readonly_key": "2rzrRZAaR7UZRK3UbUId8xmFzd4-r",
"updated_at": "2013-10-11T11:18:06+09:00",
"user_id": 2
}
}
}
我試圖把打印這樣的鏈接的所有名稱:
$.post("http://0.0.0.0:9292/api/links", function(data) {
document.getElementById("test").innerHTML = data[link][0].name;
});
,但它不工作。 我怎樣才能grub所有的名字,並把它放在html中?