JPA - 選擇多對多場

Question

我有以下實體：

@Entity 
@Data 
@EqualsAndHashCode(callSuper = true) 
@NoArgsConstructor 
@AllArgsConstructor 
public class Seat extends AbstractEntity<Long> { 
    @ManyToOne 
    private Performance performance; 

    @ManyToMany 
    private List<Rate> availableRates; 
} 

我想在JPQL執行以下查詢：

SELECT DISTINCT s.availableRates FROM Seat s WHERE :performance = s.performance 

，但我一直有如下錯誤

無法準備聲明; SQL [select count（distinct。）as col_0_0_ from seat seat0_，seat_available_rates availabler1_，rate rate2_ where seat0_.identifier = availabler1_.seat_identifier and availabler1_.available_rates_identifier = rate2_.identifier and？= seat0_.performance_identifier];嵌套的異常是org.hibernate.exception.SQLGrammarException：無法準備語句

如何編寫正確的查詢？

Answer 1

嘗試此查詢：

SELECT DISTINCT r FROM Seat s JOIN s.availableRates r WHERE s.performance = :performance