如何在java中設置數字名稱

Question

我試圖設計一個遊戲，玩Hi/Lo紙牌遊戲，直到用戶在連續獲得4個正確的答案，儘管theres與代碼的問題..我不知道如何一旦用戶指出「較高」，「較低」或「相等」是他們將最後'cardGenerated'數字與之比較的數字，那麼彈出卡號。

現在，它將它與用戶不知道或未知的數字進行比較，因此他們不知道他們是對還是錯。我知道我可以只添加「nextCard」可變進showOptionDialog輸出雖然我寧願只是有一個號碼被輸出，所以如果程序打印：

"The Card pulled is the 9 
Is the next card Higher, Lower or Equal?" 

輸出的下一個號/卡號是多少用戶正在比較以前的數字（9）和。

此外，

我已經設置了常量，但我不知道如何使它所以不是打印11，12，13，1，它打印JACK，後，王，ACE，和什麼不。

import java.util.Random; 
import javax.swing.JOptionPane; 

public class HiLo { 

public static final int JACK = 11; 
public static final int QUEEN = 12; 
public static final int KING = 13; 
public static final int ACE = 1; 

    public static void main(String[] args) { 

     int correctGuesses = 0; 

     Random generator = new Random(); 
     int currentCard; 
     int nextCard = generator.nextInt(KING+1); 

     while (correctGuesses < 4) 
     {   
      currentCard = nextCard; 
      nextCard = generator.nextInt(KING+1); 

      Object[] options = {"Higher", 
       "Lower", 
       "Equal"}; 
      int Input = JOptionPane.showOptionDialog(null, 
       "The Card pulled is the " + currentCard + 
       " \nis the next card Higher, Lower or Equal?", 
       "HiLo Card Game", 
      JOptionPane.YES_NO_CANCEL_OPTION, 
      JOptionPane.QUESTION_MESSAGE, 
      null, options, options[0]); 

      if (nextCard > currentCard && Input == JOptionPane.YES_OPTION) 
      { 
       correctGuesses++; 
      } 
      else if (nextCard > currentCard && Input == JOptionPane.NO_OPTION) 
      { 
       correctGuesses = 0; 
      } 

      else if (nextCard > currentCard && Input == JOptionPane.CANCEL_OPTION) 
      { 
       correctGuesses = 0; 
      } 

      else if (nextCard < currentCard && Input == JOptionPane.YES_OPTION) 
      { 
       correctGuesses = 0; 
      } 

      else if (nextCard < currentCard && Input == JOptionPane.NO_OPTION) 
      { 
       correctGuesses++; 
      } 

      else if (nextCard < currentCard && Input == JOptionPane.CANCEL_OPTION) 
      { 
       correctGuesses = 0; 
      } 

      else if (nextCard == currentCard && Input == JOptionPane.YES_OPTION) 
      { 
       correctGuesses = 0; 
      } 

      else if (nextCard == currentCard && Input == JOptionPane.NO_OPTION) 
      { 
       correctGuesses = 0; 
      } 

      else if (nextCard == currentCard && Input == JOptionPane.CANCEL_OPTION) 
      { 
       correctGuesses++; 
      }  
     } 

     JOptionPane.showMessageDialog(null, "Congratulations, You guessed correctly 4 times" 
       + "\nthe Last Card was the " + nextCard + " resart to play again"); 
    } 

} 

Answer 1

如果你想變量不包含單個循環迭代中（和你的問題希望你能在兩次迭代使用nextCard值），你不要在循環中聲明它。每次迭代您也不需要新的生成器或選項對象。

Random generator = new Random(); 
int currentCard; 
int nextCard = generator.nextInt(KING+1); 
while (correctGuesses < 4) 
{ 
    currentCard = nextCard; 
    nextCard = generator.nextInt(KING+1); 
    ... 
} 

至於卡印刷 - 你或許應該創建一個卡枚舉，一個包含需要打印的護理相關信息（值，套件）以及被覆蓋的toString方法。寫作應該很簡單。

Answer 2

嵌套，如果是凌亂。你應該簡化，以免你一遍又一遍地重新評估同樣的事情。例如，你的前三層評估nextCard > cardGenerated。如果您將其提取到自己的if，代碼將更具可讀性。你也可以用switch()代替評價(Input == JOptionPane.XX_OPTION)的另一部分：

 if(nextCard > cardGenerated) 
     { 
      switch(input) 
      { 
       case JOptionPane.YES_OPTION: 
        correctGuesses++; 
        break; 
       case JOptionPane.NO_OPTION: 
       case JOptionPane.CANCEL_OPTION: 
        correctGuesses = 0; 
        break; 
       default: 
        System.out.println("Should never happen, but default case should always be included"); 
      } 
     } 
     else if(nextCard < cardGenerated) 
     { 
      switch(input) 
      { 
       case JOptionPane.NO_OPTION: 
        correctGuesses++; 
        break; 
       case JOptionPane.YES_OPTION: 
       case JOptionPane.CANCEL_OPTION: 
        correctGuesses = 0; 
        break; 
       default: 
        System.out.println("Should never happen, but default case should always be included"); 
      } 
     } 
     else 
     { 
      switch(input) 
      { 
       case JOptionPane.CANCEL_OPTION: 
        correctGuesses++; 
        break; 
       case JOptionPane.YES_OPTION: 
       case JOptionPane.NO_OPTION: 
        correctGuesses = 0; 
        break; 
       default: 
        System.out.println("Should never happen, but default case should always be included"); 
      } 
     }