休眠過濾器不起作用

-1

我使用Hibernate，我想用Hibernate過濾器選項過濾實體。但過濾器將被忽略。工作區實體包括一個用戶實體。而且我希望只有doesent這個用戶的所有工作空間實體在數據庫的電子郵件字段中有一個NULL值。我期待您的迴音。由於休眠過濾器不起作用

工作區

@Entity 
     @Table(name = "WORKSPACEENTITY", schema = "pwdmanager") 
     @PrimaryKeyJoinColumn(name = "workspace_id", referencedColumnName = "id") 
     @Setter 
     @Getter 

     @FilterDef(name = "FILTER") 
     public class DBWorkspaceEntity{ 

      @OneToMany(fetch = FetchType.LAZY, cascade = CascadeType.ALL, mappedBy = "wkse_space") 
      private List<DBPasswordEntity> pwde_password; 

      @OneToOne(fetch = FetchType.EAGER) 

      @Filters({ 
        @Filter(name="FILTER", condition="{u}.usre_email is not null", aliases={@SqlFragmentAlias(alias="u", entity=DBUserEntity.class)}), 
      }) 
      private DBUserEntity usre_user; 
    }

用戶

@Entity 
    @Table(name = "USERENTITY", schema = "pwdmanager") 
    @Setter 
    @Getter 
    @PrimaryKeyJoinColumn(name = "user_id", referencedColumnName = "id") 
    public class DBUserEntity{ 

     @Basic 
     @Column(name = "USRE_EMAIL", nullable = true, length = 1024) 
     private String usre_email; 
    }

休眠

public class MasterDao{ 
    private Session session; 
    private Transaction transaction; 
    private SessionFactory sessionFactory; 

    public void prepare() { 
     sessionFactory = HibernateUtil.getSessionFactory(); 
     this.session = sessionFactory.openSession(); 
    } 

    public void filter(final DBUserEntity usr) { 
     try { 
      session.enableFilter("FILTER"); 
      Query query = session.createQuery("FROM " + DBWorkspaceEntity.class.getSimpleName()); 
      List<DBWorkspaceEntity> result = query.list(); 
      session.disableFilter("FILTER_USER"); 

     } catch (final HibernateException ex) { 
      log.error(ex); 
     } 
    } 
}

來源

2017-03-19 Dominik

我認爲，usre_emai l在過濾條件中應該是列名。

USRE_EMAIL

來源

2017-03-19 16:28:06 rathna

我將過濾條件更改爲USRE_EMAIL IS NOT NULL，並且得到相同的結果 – Dominik

休眠過濾器不起作用

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