由於行System.out.println(sendURL.substring(0, sendURL.lastIndexOf("/")));
sendURL不爲空,它具有值。任何人都請幫我解決這個問題。提前致謝!無法編譯JSP,Eception:org.apache.jasper.JasperException
消息
描述服務器遇到阻止其完成此請求一個內部錯誤()。
異常
org.apache.jasper.JasperException: An exception occurred processing JSP page /jsp/authenticate.jsp at line 47
44: config = getServletConfig();
45: String localStoreurl=application.getInitParameter("localstorefile");
46: String domain=application.getInitParameter("domain");
47: System.out.println(sendURL.substring(0, sendURL.lastIndexOf("/")));
48: %>
49: <html xmlns="http://www.w3.org/1999/xhtml">
50: <head>
Stacktrace: org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:519)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:428)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:313)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:260)
javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
root cause java.lang.NullPointerException
org.apache.jsp.jsp.authenticate_jsp._jspService(authenticate_jsp.java:103)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:386)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:313)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:260)
javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
note The full stack trace of the root cause is available in the Apache Tomcat/6.0.30 logs.
的Apache Tomcat/6.0.30
你爲什麼不在這裏發佈完整的scriptlet?或多或少清楚地表明錯誤與'sendURL'變量有關,但如果我們不知道如何聲明/初始化它,我們不能提供幫助 –