比較Integer類型的BinarySearchTree節點

Question

如何比較我的數據結構中Integer類型的2個Tree節點？如果我使用==它給NullPointerException異常誤差值大於128 ...

public int brElNaPutanji(BNode<Integer> tekuci, BNode<Integer> kraj){ 
    if (tekuci == kraj) 
     return 0; 
    int trt = kraj.info; 
    int prt = tekuci.info; 
    if (trt < prt) 
     return 1 + brElNaPutanji(tekuci.left, kraj); 
    else 
     return 1 + brElNaPutanji(tekuci.right, kraj); 
} 

這裏是B節點類

class BNode<E extends Comparable<E>> { 

public E info; 
public BNode<E> left; 
public BNode<E> right; 

public BNode(E info) { 
    this.info = info; 
    left = null; 
    right = null; 
} 

public BNode(E info, BNode<E> left, BNode<E> right) { 
    this.info = info; 
    this.left = left; 
    this.right = right; 
} 

} 

Answer 1

使用number1.equals(number2)代替==爲==只檢查，如果他們在相同的內存區域，可能並不總是正確的。