大家好我想顯示記錄。但是,我不想在listview中顯示它們,而是在textview中顯示它們。我已經在做新的換行\ n來完成這個技巧,但是在我的程序中,它只是顯示了第一條記錄。在textview中顯示多行Android
這是我到目前爲止已經試過:
MainActivity.class
Bundle extras = getIntent().getExtras();
if (extras != null) {
dog_name = extras.getString("dog_name");
cursor = dbHelper.fetchbBreedByName(dog_name);
strID = cursor.getString(0);
strDesc = cursor.getString(cursor.getColumnIndexOrThrow("description"));
strDiet = cursor.getString(cursor.getColumnIndexOrThrow("diet"));
strShelter = cursor.getString(cursor.getColumnIndexOrThrow("shelter"));
strHygiene = cursor.getString(cursor.getColumnIndexOrThrow("hygiene"));
strMedication = cursor.getString(cursor.getColumnIndexOrThrow("medication"));
strBreed = cursor.getString(cursor.getColumnIndexOrThrow("breed"));
Log.d("Animal ID", "Animal ID is " + strID + " and breed is " + strBreed);
Log.d("Desc", "Desc " + strDesc);
Description.setText(strDesc);
Diet.setText(strDiet);
Shelter.setText(strShelter);
Hygene.setText(strHygiene);
Medication.setText(strMedication); }
DBHelper.class
public Cursor fetchbBreedByName(CharSequence inputText) throws SQLException {
Cursor mCursor = null;
if (inputText == null || inputText.length() == 0) {
mCursor = myDataBase.query(DB_TABLE, new String[] { KEY_ID, KEY_DESCRIPTION,
KEY_DIET, KEY_SHELTER, KEY_HYGIENE, KEY_MEDICATION, KEY_BREED },
null, null, null, null, null);
}
else {
String qry = "SELECT _id, description, diet, shelter, hygiene, medication, " +
"breed FROM tblAnimalInfo WHERE breed LIKE '%" + inputText + "%';";
mCursor = myDataBase.rawQuery(qry, null);
//mCursor = myDataBase.query(DB_TABLE, new String[] { KEY_ID, KEY_DESCRIPTION,
// KEY_DIET, KEY_SHELTER, KEY_HYGIENE, KEY_MEDICATION, KEY_BREED },
// KEY_BREED + " like '%" + inputText + "%'", null, null, null, null);
}
if (mCursor != null) {
mCursor.moveToFirst();
}
return mCursor;
}
我不知道什麼是錯的。請幫我弄清楚我的代碼中缺少什麼。提前致謝。
感謝您的回答,我可能會問什麼應該放在訪問記錄中我的應用程序? – Dunkey
用cursor.getString()讀取記錄的所有字段,你已經在做它了。 – sjdutta