在mysql中處理日期？

我有這個很長的mysql查詢，並試圖找到獲取行比較老，然後給出日期$lastmsg。在mysql中處理日期？

這是使用的代碼IM：

$result="SELECT 
       u.username, u.picture,m.id, m.user_note, m.reply_id, m.reply_name, m.recycle_id, m.recycle_name, m.dt 
       FROM 
       relationships r, 
       notes m, 
       user u 
       WHERE 
       m.user_id = r.leader 
       AND 
       r.leader = u.user_id 
       AND 
       r.listener = ".$_SESSION['user_id']." 
      UNION 
       select username, picture,id, user_note, reply_id, reply_name, recycle_id, recycle_name, dt 
       from user u, notes b 
       where u.user_id = b.user_id 
       AND 
       b.user_id =".$_SESSION['user_id']." 
       AND 
     WHERE dt < '$lastmsg' 
       ORDER BY dt DESC LIMIT 10"; 

mysql_query($result) or die(mysql_error().$result);

抱歉長亂碼，查詢工作，直到我加入這個$ lastmsg where子句。

p.s. dt爲DATETIME 和$ lastmsg是2010-09-20 12:53:43

錯誤即時得到的是：

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'where dt <'2010-09-20 12:53:43' ORDER BY dt DESC LIMIT 10' at line 20SELECT u.username, u.picture,m.id, m.user_note, m.reply_id, m.reply_name, m.recycle_id, m.recycle_name, m.dt FROM relationships r, notes m, user u WHERE m.user_id = r.leader AND r.leader = u.user_id AND r.listener = 2 UNION select username, picture,id, user_note, reply_id, reply_name, recycle_id, recycle_name, dt from user u, notes b where u.user_id = b.user_id and b.user_id =2 and where dt <'2010-09-20 12:53:43' ORDER BY dt DESC LIMIT 10

來源

2010-09-20 getaway

如果'$ lastmasg' =='2010-09-20 12：53：43''多餘的引用會導致語法錯誤。 mysql報告的錯誤是什麼？ – Wrikken 2010-09-20 17:06:55

我剛編輯我的問題，錯誤是他們！ – getaway 2010-09-20 17:08:14

  AND 
    WHERE dt < '$lastmsg'

這是無效的語法。刪除'WHERE'。

來源

2010-09-20 17:08:13

乾杯:)）））我很盲目 – getaway 2010-09-20 17:11:42

在mysql中處理日期？

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