我正在使用cordova媒體插件來錄製voice.Once我記錄它。我想把它發送到服務器。爲此,我正在使用FileUpload和FileTransfer.But我面臨着獲取錄製文件的問題。如何獲取錄製的音頻文件?我已經通過cordova文件插件文檔,但沒有正確理解。我發現這個錯誤代碼1我使用科爾多瓦和PHP,它不爲我工作,你可以幫助請。傳輸音頻到服務器cordova
<html>
<head>
<script src="cordova.js"></script>
<script src="mvc/js/jquery.min.js"></script>
<script>
var filename;
var mediaRec;
function recordAudio() {
filename = new Date().getTime();
mediaRec = new Media(filename, onSuccess, onError);
mediaRec.startRecord();
}
function onSuccess(){
alert("onSuccess " +filename);
}
function onError(){}
function stopRecord(fileName){
mediaRec.stopRecord();
uploadVoice(filename,"");
}
function uploadVoice(fileName, dirName) {
var win = function (r) {
alert("Code = " + r.responseCode);
console.log("Response = " + r.response);
console.log("Sent = " + r.bytesSent);
};
var fail = function(error) {
alert("fail "+error.code);
alert("Source = " + error.source);
alert("Target = " + error.target)
};
// file system fail
var fsFail = function(error) {
alert("file system error");
//alert("fsfail "+error.code);
};
var dirFail = function(error) {
alert("Directory error");
};
var fileURI;
var gotFileSystem = function (fileSystem) {
fileSystem.root.getDirectory(dirName, {
create: false
}, function (dataDir) {
fileURI = dataDir.toURL();
fileURI = fileURI + '/' + fileName;
var options = new FileUploadOptions();
options.fileKey = "file";
options.fileName = fileURI.substr(fileURI.lastIndexOf('/') + 1);
options.mimeType = "Audio/3gpp";
options.chunkedMode = false;
options.headers = { Connection: "close" };
var ft = new FileTransfer();
ft.upload(fileURI, "url", win, fail, options);
}, dirFail);
};
window.requestFileSystem(LocalFileSystem.PERSISTENT, 0, gotFileSystem, fsFail);
}
</script>
<body>
<button onClick="recordAudio();">Start</button><br/><br/>
<button onClick="stopRecord();">Stop</button>
</body>
</head>
你說「錯誤代碼1」?你從哪裏得到它?哪條線?這是一個彙編問題嗎? – e666
文件傳輸不起作用的問題給我錯誤代碼1 –