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我有一個應用程序在用戶搖動手機後顯示UIWebView。它完美的工作,直到用戶點擊web視圖中的鏈接。一旦用戶點擊鏈接,他們必須點擊屏幕上的空白區域才能使搖動功能重新開始工作。iPhone MotionShake在點擊鏈接後停止工作
正如您在下面看到的,我已經包含了canBecomeFirstResponder和webViewDidFinishLoad函數。請幫忙!
#import "phonetiltViewController.h"
@implementation phonetiltViewController
-(void)viewDidAppear:(BOOL)animated {
[self becomeFirstResponder];
}
-(void)viewDidDisappear:(BOOL)animated {
[self resignFirstResponder];
}
- (BOOL)canBecomeFirstResponder
{ // Shake gesture pops to top. If you don't want this override and
return YES;
}
- (void)motionEnded:(UIEventSubtype)motion withEvent:(UIEvent *)event {
if (event.subtype == UIEventSubtypeMotionShake) {
[webView loadRequest: [NSURLRequest requestWithURL: [NSURL URLWithString:@"http://www.google.com"]]];
}
}
- (void)webViewDidFinishLoad:(UIWebView *)webView {
[self becomeFirstResponder];
}
謝謝!我已將加速度值設置爲「2」。 「2」是加速度值的限制嗎? – Brandon
不,我不知道限制我已經看到像6和8的價值。如果你想檢查限制,你必須檢查文檔。 –