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我已經創建了一個API,所以android應用程序可以連接到網站我面對的問題是我無法提供訪問權限以便將圖像上傳到服務器,至此我已創建所以圖像將作爲base64代碼保存,但主要問題是,當每個API調用和圖像上傳它給我一個圖像錯誤,沒有找到無法加載文件流。下面是我得到用於上傳圖像的API不起作用
<b>Warning</b>: fopen(uploads/testimg.png): failed to open stream: No such
file or directory in <b>/home/begazed/public_html/api/classfiles/Photo.php</b> on line <b>87</b><br />
<br />
<b>Warning</b>: fwrite() expects parameter 1 to be resource, boolean given in <b>/home/begazed/public_html/api/classfiles/Photo.php</b> on line <b>88</b><br />
<br />
<b>Warning</b>: fclose() expects parameter 1 to be resource, boolean given in <b>/home/begazed/public_html/api/classfiles/Photo.php</b> on line <b>89</b><br />
{"result":1,"message":"Image upload complete, Please check your php file directory"}
這個錯誤是我創建上傳圖像到服務器的功能
function upload_photo($connect, $base, $filename) {
$binary = base64_decode($base);
$query = $connect->prepare("INSERT INTO test_photo (filename) VALUES (:filename)");
$query->execute(array(':filename' => $filename));
header('Content-Type: bitmap; charset=utf-8');
$file = fopen('uploads/'.$filename, 'wb');
fwrite($file, $binary);
fclose($file);
$err['result'] = 1;
$err['message'] = 'Image upload complete, Please check your php file directory';
return json_encode($err);
}
從那裏請求被處理了主要的API文件
switch($action)
{
case 'upload_photo':
$base = $_REQUEST['image'];
$filename = $_REQUEST['filename'];
echo $retval = $photo->upload_photo($connect, $base, $filename);
break;
default:
echo "Invalid Request";
break;
}
tthis是用於撥打電話的網址
www.domainname.com/api/api.php?action=upload_photo & fimename =(文件名)&圖像= iamge NAE
誰能幫我如果你的PHP的來解決這個錯誤
沒有人可以幫助我:-( –