如何繪製在一條垂直線上點的中位值控制圖中的R

Question

需要創建一個圖表，看起來像這樣：

我幾乎沒有，只是缺少其垂直繪製的各個點。

這裏的數據：

q6 <- structure(list(x1 = c(0.0629, 0.063, 0.0628, 0.0634, 0.0619, 
0.0613, 0.063, 0.0628, 0.0623, 0.0631, 0.0635, 0.0623, 0.0635, 
0.0645, 0.0619, 0.0631, 0.0616, 0.063, 0.0636, 0.064, 0.0628, 
0.0615, 0.063, 0.0635, 0.0623), x2 = c(0.0636, 0.0631, 0.0631, 
0.063, 0.0628, 0.0629, 0.0639, 0.0627, 0.0626, 0.0631, 0.063, 
0.063, 0.0631, 0.064, 0.0644, 0.0627, 0.0623, 0.063, 0.0631, 
0.0635, 0.0625, 0.0625, 0.0632, 0.0629, 0.0629), x3 = c(0.064, 
0.0622, 0.0633, 0.0631, 0.063, 0.0634, 0.0625, 0.0622, 0.0633, 
0.0633, 0.0638, 0.063, 0.063, 0.0631, 0.0632, 0.063, 0.0631, 
0.0626, 0.0629, 0.0629, 0.0616, 0.0619, 0.063, 0.0635, 0.063), 
    x4 = c(0.0635, 0.0625, 0.0633, 0.0632, 0.0619, 0.0625, 0.0629, 
    0.0625, 0.063, 0.0631, 0.0635, 0.0627, 0.063, 0.064, 0.0622, 
    0.0628, 0.062, 0.0629, 0.0635, 0.0635, 0.062, 0.0619, 0.0631, 
    0.0631, 0.0626), x5 = c(0.064, 0.0627, 0.063, 0.0633, 0.0625, 
    0.0628, 0.0627, 0.0627, 0.0624, 0.063, 0.0633, 0.0629, 0.063, 
    0.0642, 0.0635, 0.0629, 0.0625, 0.0628, 0.0634, 0.0634, 0.0623, 
    0.0622, 0.063, 0.0633, 0.0628)), .Names = c("x1", "x2", "x3", 
"x4", "x5"), class = "data.frame", row.names = c(NA, -25L)) 

下面是代碼：

range_span <- function(x) return(diff(range(x))) # function to calculate range 
# q6 <- read.table(file="/Users/.../blah.csv",header=T,sep=",") #data 
medians <- apply(q6,1,median) 
ranges <- apply(q6,1,range_span) 
centre <- mean(medians) #grand median 
Rtilde <- median(ranges) #median of ranges 

plot(medians, type="b",xaxp=c(1, 25, 24),pch=19,xlab="Sample No.",ylab="Medians",main="Median Chart for Thickness of Metal Parts") 

# code below draws the control limits 

action.limits<-c(centre+0.681*Rtilde,centre-0.681*Rtilde) 
warn.limits<-c(centre+(2/3)*0.681*Rtilde,centre-(2/3)*0.681*Rtilde) 

abline(h = centre, lty = 3, col = "black") 
v0 <-c("CL") 
mtext(side = 4, text = v0, at = centre, col = "black", las=2) 

abline(h = warn.limits, lty = 3, col = "blue") 
v1 <-c("UWL","LWL") 
mtext(side = 4, text = v1, at = warn.limits, col = "blue", las=2) 

abline(h = action.limits, lty = 3, col = "black") 
v2 <-c("UCL","LCL") # the labels for action.limits 
mtext(side = 4, text = v2, at = action.limits, col = "black", las=2) 

我敢肯定有一個簡單的解決方案，我沒有經歷過與RI都只是想給自己設定通過在課程作業中生成圖表來實現挑戰，但現在我開始耗盡時間。

• 請問points()有幫助嗎？我需要R認識到q6中的每一行都是我可能做到的樣本points(q6,c(1:25))或類似的東西？

Answer 1

因此，您的數據中的任何位置都沒有x座標（1到25），這可能會使繪圖變得困難。

q6$x = 1:25 

下一步不是嚴格必要的，但它使事情變得更加方便。我將「融化」你的數據爲長格式：

q6_long = reshape2::melt(q6, id.vars = "x") 

## just showing what it looks like now 
head(q6_long) 
# x variable value 
# 1 1  x1 0.0629 
# 2 2  x1 0.0630 
# 3 3  x1 0.0628 
# 4 4  x1 0.0634 
# 5 5  x1 0.0619 
# 6 6  x1 0.0613 

現在加點是很容易與points功能：

points(q6_long$x, q6_long$value, pch = 5)