最好的選擇是打開原來的文件進行讀取,寫入的目標文件,然後循環複製塊逐塊。在僞代碼:
f1 = open(filename1);
f2 = open(filename2, "w");
while(!f1.eof()) {
buffer = f1.read(buffersize);
err = f2.write(buffer, buffersize);
if err != NO_ERROR_CODE
break;
}
f1.close(); f2.close();
[提問者編輯]好吧,這是它的外觀在C#(它是緩慢的,但它似乎工作正常,並且給出了進步):
using System;
using System.Collections.Generic;
using System.IO;
using System.Text;
namespace LoopCopy
{
class Program
{
static void Main(string[] args)
{
if (args.Length != 2)
{
Console.WriteLine(
"Usage: LoopCopy.exe SourceFile DestFile");
return;
}
string srcName = args[0];
string destName = args[1];
FileInfo sourceFile = new FileInfo(srcName);
if (!sourceFile.Exists)
{
Console.WriteLine("Source file {0} does not exist",
srcName);
return;
}
long fileLen = sourceFile.Length;
FileInfo destFile = new FileInfo(destName);
if (destFile.Exists)
{
Console.WriteLine("Destination file {0} already exists",
destName);
return;
}
int buflen = 1024;
byte[] buf = new byte[buflen];
long totalBytesRead = 0;
double pctDone = 0;
string msg = "";
int numReads = 0;
Console.Write("Progress: ");
using (FileStream sourceStream =
new FileStream(srcName, FileMode.Open))
{
using (FileStream destStream =
new FileStream(destName, FileMode.CreateNew))
{
while (true)
{
numReads++;
int bytesRead = sourceStream.Read(buf, 0, buflen);
if (bytesRead == 0) break;
destStream.Write(buf, 0, bytesRead);
totalBytesRead += bytesRead;
if (numReads % 10 == 0)
{
for (int i = 0; i < msg.Length; i++)
{
Console.Write("\b \b");
}
pctDone = (double)
((double)totalBytesRead/(double)fileLen);
msg = string.Format("{0}%",
(int)(pctDone * 100));
Console.Write(msg);
}
if (bytesRead < buflen) break;
}
}
}
for (int i = 0; i < msg.Length; i++)
{
Console.Write("\b \b");
}
Console.WriteLine("100%");
Console.WriteLine("Done");
}
}
}
至少使用100KB更好1MB的緩存。這將極大地加速文件複製! – 2008-11-19 15:02:55