2016-05-15 97 views
0

我得到了類似的錯誤。
未捕獲PDOException:SQLSTATE [21000]:基數違規:1241操作數應包含1列(S)未捕獲的PDOException:SQLSTATE [21000]:基數違規:1241操作數應該包含1列

if ($_POST['submit'] ?? '' == "Log In") { 

    $query = "SELECT * FROM member WHERE (email, password) LIKE (:email, :password)"; 

    $stmt = $link -> prepare($query); 
    $stmt -> bindValue(':email', $_POST['loginemail'], PDO::PARAM_STR); 
    $stmt -> bindValue(':password', md5(md5($_POST['loginemail']).$_POST['loginpassword']), PDO::PARAM_STR); 
    $stmt -> execute(); 
    $rows = $stmt -> fetchAll(); 

} 

但沒有錯誤的這一說法。

$sql = "SELECT ko_name FROM dogBREEDS WHERE dogBREEDS.ko_name LIKE (:keyword) ORDER BY id ASC LIMIT 0, 10"; 
$query = $pdo->prepare($sql); 
$query->bindParam(':keyword', $keyword, PDO::PARAM_STR); 
$query->execute(); 
$list = $query->fetchAll(); 

我該如何解決這個問題?和有什麼區別?

回答

0

$query = "SELECT * FROM member WHERE (email, password) LIKE (:email, :password)";

這個SQL是不是在正確的語法權SQL。 LIKE(或者看看這裏MySQL LIKE Clause)不能使用這樣的,試試這個請;)

$query = "SELECT * FROM member WHERE email LIKE (:email) and password LIKE (:password)"; 
0

我只是改變了這個樣子。

$query = "SELECT ID FROM member WHERE email=:email AND password=:password"; 

$stmt = $link -> prepare($query); 
$stmt -> bindParam(':email', $_POST['loginemail'], PDO::PARAM_STR); 
$stmt -> bindValue(':password', md5(md5($_POST['loginemail']).$_POST['loginpassword']), PDO::PARAM_STR); 
$stmt -> execute(); 
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