如何將$ _POST值從表單發送到圖像標記?圖像由另一個帶有後期值的PHP文件創建。 代碼示例:
<form name="grafiks" action="<?php echo $_SERVER['PHP_SELF'];?>" method="post" onsubmit="check()">
<select name="kolsk" onchange="this.form.submit()" >
<option></option>
<option <?php if(isset($_POST['kolsk']) && $_POST['kolsk'] == '1') echo 'selected="selected"' ?> value="1">1</option>
<option <?php if(isset($_POST['kolsk']) && $_POST['kolsk'] == '2') echo 'selected="selected"' ?> value="2">2</option>
<option <?php if(isset($_POST['kolsk']) && $_POST['kolsk'] == '3') echo 'selected="selected"' ?> value="3">3</option>
</select>
</form>
<?php
if(isset($_POST['kolsk'])){
$kolsk = $_POST['kolsk'];
}
echo '<img src = "myplot2.php" ?$kolsk >';
?>
我不明白。你的意思是你想讓POST變量'kolsk'在圖像的'src'屬性中? –