npyscreen - switchForm（formid）error

Question

我正在使用npyscreen，我想了解switchForm方法的工作原理。 我做了一個小例子，我從文檔和this question（這沒有回答我的問題）。 我的代碼：

import npyscreen 
import sys 

class myEmployeeForm(npyscreen.ActionForm): 
    def afterEditing(self): 
     self.parentApp.setNextForm('Second') 

    def create(self): 
     self.myName = self.add(npyscreen.TitleText, name='Name') 
     self.myDepartment = self.add(npyscreen.TitleSelectOne, scroll_exit=True, max_height=3, name='Department', values = ['Department 1', 'Department 2', 'Department 3']) 
    self.myDate  = self.add(npyscreen.TitleDateCombo, name='Date Employed') 

class secondOne(npyscreen.ActionForm): 
    def afterEditing(self): 
    self.parentApp.setNextForm(None) 

    def create(self): 
    self.myName  = self.add(npyscreen.TitleText, name='Name') 
    self.myDepartment = self.add(npyscreen.TitleSelectOne, scroll_exit=True, max_height=3, name='Department', values = ['Department 1', 'Department 2', 'Department 3']) 
    self.myDate  = self.add(npyscreen.TitleDateCombo, name='Date Employed') 
    self.add_handlers({"^Q": sys.exit, "^T": self.changingForm('Second')}) 

    def changingForm(self, name): 
    self.parentApp.switchForm(name) 

class MyApplication(npyscreen.NPSAppManaged): 
    def onStart(self): 
    self.addForm('MAIN', myEmployeeForm, name='New Employee') 
    self.addForm('Second', secondOne, name='New start') 

if __name__ == '__main__': 
    TestApp = MyApplication().run() 

有人能向我解釋爲什麼我得到這個錯誤：

File "/home/MyName/.local/lib/python3.5/site-packages/npyscreen/apNPSApplicationManaged.py", line 81, in switchForm 
self._THISFORM.editing = False 
AttributeError: 'MyApplication' object has no attribute '_THISFORM' 

感謝您的支持:)

Answer 1

我的錯誤比npyscreen多掛蟒蛇。 請看這裏enter link description here 謝謝