如何從mysql中的連接表中獲取不等行？

Question

我有兩個表如下

user_job_applied

company_viewed_user

我想爲user_job_applied表中的相關job_id取不在company_viewed_user表中的行。 我寫了下面的查詢，但它沒有抓住

SELECT 
    `user_job_applied`.user_id 
FROM 
    `user_job_applied` 
LEFT JOIN 
    `company_viewed_user` 
ON 
    `company_viewed_user`.user_id ON `company_viewed_user`.user_id = `user_job_applied`.user_id        
WHERE 
    `company_viewed_user`.user_id IS NULL AND 
    `company_viewed_user`.emp_id IN (SELECT user_id 
            FROM company_user 
            WHERE company_id='1') 
AND 
    `user_job_applied`.job_id = '1'; 

輸出應該如下

Answer 1

想在移動EMP_ID條件，左連接語句從where子句

SELECT 
`user_job_applied`.user_id 
FROM 
`user_job_applied` 
LEFT JOIN `company_viewed_user` ON `company_viewed_user`.user_id = `user_job_applied`.user_id AND 
                   `company_viewed_user`.emp_id IN (SELECT user_id FROM company_user WHERE company_id='1')        
WHERE 
`company_viewed_user`.user_id IS NULL AND       
`user_job_applied`.job_id = '1'; 

Answer 2

您可以使用下面的查詢

SELECT uja.user_id 
FROM `user_job_applied` AS uja 
LEFT JOIN `company_viewed_user` AS cvu ON cvu.user_id = uja.user_id        
WHERE cvu.user_id IS NULL; 

如果你想添加任何其他過濾器，然後你可以包括你自己或讓我知道。

增加了新的條件

SELECT uja.user_id 
FROM `user_job_applied` AS uja 
JOIN company_user AS cu ON cu.user_id=uja.emp_id 
LEFT JOIN `company_viewed_user` AS cvu ON cvu.user_id = uja.user_id        
WHERE uja.job_id=1 AND cu.company_id=1 AND cvu.user_id IS NULL; 

注意：如果JOB_ID和COMPANY_ID沒有整型，然後用引號括起來。