發佈至燒瓶

Question

我有一個PHP應用程序，它的帖子可變信息加入燒瓶中的應用程序（其中做了一些計算，並返回一個結果）。我在win7上本地運行

當我使用postman測試URL「127.0.0.1:5000/index」時，我得到一個200狀態碼（截圖）。然而，當PHP應用程序的帖子在燒瓶應用程序，我得到：

The requested URL was not found on the server. If you entered the URL manually please check your spelling and try again. 

我使用curl和冗長的輸出是：

* About to connect() to 127.0.0.1 port 5000 (#0) 
* Trying 127.0.0.1... 
* connected 
* Connected to 127.0.0.1 (127.0.0.1) port 5000 (#0) 
> POST /index/ HTTP/1.1 
User-Agent: Mozilla/4.0 (compatible; MSIE 7.0; Windows NT 6.0) 
Host: 127.0.0.1:5000 
Accept: */* 
Content-Length: 338 
Expect: 100-continue 
Content-Type: multipart/form-data; boundary=----------------------------d5cb02e2edea 
< HTTP/1.1 100 Continue 
* HTTP 1.0, assume close after body 
< HTTP/1.0 404 NOT FOUND 
< Content-Type: text/html 
< Content-Length: 233 
< Server: Werkzeug/0.10.4 Python/2.7.5 

我的PHP代碼如下所示：

$data= array('a'=>$a, 'token'=>$token); 
    $url="http://127.0.0.1:5000/index/"; 
    $output = $this->my_model->get_data($url, $data); 

public function get_data($url,$postFieldArray=FALSE) { 

$ch = curl_init(); 
curl_setopt($ch, CURLOPT_COOKIEJAR, $cookieFile); 
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, TRUE); 
curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE); 
curl_setopt($ch, CURLOPT_USERAGENT, "Mozilla/4.0 (compatible; MSIE 7.0; Windows NT 6.0)"); 
if ($postFieldArray!= FALSE) { 
    curl_setopt($ch, CURLOPT_POST, TRUE); 
    curl_setopt($ch, CURLOPT_POSTFIELDS, $postFieldArray); //for django 
} 
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, FALSE); 
curl_setopt($ch, CURLOPT_VERBOSE, true); 
curl_setopt($ch, CURLOPT_STDERR, $verbose); 
curl_setopt($ch, CURLOPT_URL, $url); 
$html = curl_exec($ch); 
curl_close($ch); 
....... 

return $result; 
} 

簡體瓶應用：

app = Flask(__name__) 
app.debug = True 

@app.route('/') 
def hello_world(): 
    return 'Hello World!' 

@app.route('/index',methods=['POST']) 
def index(): 

    token = request.form['token'] 
    a = request.form['a'] 
    ...... 
    return 

if __name__ == '__main__': 
    app.run() 

我在做什麼錯了？

Answer 1

您在PHP代碼中的$url變量中有一個斜線。這是行不通的，因爲你的Flask代碼中沒有尾隨的斜線。看here更多信息，下