的Python INT到百分之

Question

我需要monthlyPayment作爲百分比的這樣代替範圍= [4，5，6，7，8] 我需要範圍= [0.04，0.05，0.06，0.07，0.08]

你知道如何做到這一點，並且仍然totalPayment

得到計算

import math 

loanAmt=int(input("Enter the Amount (greater then 0) of the Loan: ")) 

numYears=int(input("Enter the number of years as an integer: ")) 

for monthlyRate in range(4,9): 

    monthlyPayment = loanAmt * monthlyRate/(1 - math.pow(1/(1 + monthlyRate), numYears * 12)) 

    totalPayment = monthlyPayment * numYears * 12 
    print("{0:.0f}%".format(monthlyRate),'\t','$%.2f' %monthlyPayment,'\t','\t','$%.2f' %totalPayment) 

Answer 1

您可以使用此：

for monthlyRate in (x/100.0 for x in range(4,9)): 
    print monthlyRate 

0.04 
0.05 
0.06 
0.07 
0.08 

Answer 2

或者你也可以使用一個list comprehension

percent_rate = [rate/100.0 for rate in monthly_rate] 
# where monthly_rate is the list of all ints like [4, 5, 6, 7, 8]