使用XSLT得到最後一組兄弟前代

Question

我需要將<amendment/>元素拉到<sectionid/>,<amendmenttext/>和<sponsor/>元素（如果可用）。

下面是一個例子：

來自：

<root> 
     <amendment> 
      <id>1</id> 
      <text>some text</text> 
     </amendment> 
     <sectionid>A</sectionid> 
     <sponsor>jon</sponsor> 
     <sponsor>peter</sponsor> 
     <amendment> 
      <id>8</id> 
      <text>some text</text> 
     </amendment> 
     <sectionid>B</sectionid> 
     <sponsor>matt</sponsor> 
     <sponsor>ben</sponsor> 
     <amendmenttext>some intro text</amendmenttext> 
     <amendment> 
      <id>5</id> 
      <text>some text</text> 
     </amendment> 
     <amendment> 
      <id>4</id> 
      <text>some text</text> 
     </amendment> 
     <sponsor>max</sponsor> 
     <amendment> 
      <id>6</id> 
      <text>some text</text> 
     </amendment> 
     <amendment> 
      <id>7</id> 
      <text>some text</text> 
     </amendment> 

</root> 

到：

<root> 
     <amendment>     
      <id>1</id> 
      <text>some text</text> 
     </amendment>   
     <amendment> 
      <sectionid>A</sectionid> 
      <sponsor>jon</sponsor> 
      <sponsor>peter</sponsor> 
      <id>8</id> 
      <text>some text</text> 
     </amendment> 
     <amendment> 
      <sectionid>B</sectionid> 
      <sponsor>matt</sponsor> 
      <sponsor>ben</sponsor> 
      <amendmenttext>some intro</amendmenttext> 
      <id>5</id> 
      <text>some text</text> 
     </amendment> 
     <amendment> 
      <sectionid>B</sectionid> 
      <sponsor>matt</sponsor> 
      <sponsor>ben</sponsor> 
      <id>4</id> 
      <text>some text</text> 
     </amendment> 
     <amendment> 
      <sectionid>B</sectionid> 
      <sponsor>max</sponsor> 
      <id>6</id> 
      <text>some text</text> 
     </amendment> 
     <amendment> 
      <sectionid>B</sectionid> 
      <sponsor>max</sponsor> 
      <id>7</id> 
      <text>some text</text> 
     </amendment> 

</root> 

注1：<sectionid/>元件適用於所有<amendments/>下一<sectionid/>

之前注2：<sponsor/>元素適用於所有<amendments/>之前的下一個<sponsor/>列表。

注3：//amendment/id的值不是連續的。

注4：<amendment/>不能有<sponsor/>或<sectionid/>作爲前兄弟。

注5：<amendmenttext>僅適用於以下<amendment/>

這怎麼轉型與XSLT 1.0完成。

Answer 1

這個樣式表（相同的答案比以前只是一個規則）：

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> 
    <xsl:strip-space elements="*"/> 
    <xsl:template match="node()|@*"> 
     <xsl:param name="pSectionId" select="/.."/> 
     <xsl:param name="pSponsors" select="/.."/> 
     <xsl:variable name="vSectionid" select="self::sectionid"/> 
     <xsl:variable name="vSponsor" select="self::sponsor"/> 
     <xsl:variable name="vAmendment" select="self::amendment"/> 
     <xsl:if test="not($vSectionid|$vSponsor)"> 
      <xsl:copy> 
       <xsl:apply-templates select="@*"/> 
       <xsl:copy-of select="$pSectionId[$vAmendment]"/> 
       <xsl:copy-of select="$pSponsors[$vAmendment]"/> 
       <xsl:apply-templates select="node()[1]"/> 
      </xsl:copy> 
     </xsl:if> 
     <xsl:apply-templates select="following-sibling::node()[1]"> 
      <xsl:with-param name="pSectionId" 
          select="$pSectionId[not($vSectionid)]|$vSectionid"/> 
      <xsl:with-param name="pSponsors" 
          select="$pSponsors[not($vSponsor) or 
               current() 
                /preceding-sibling::node()[1] 
                /self::sponsor] | 
            $vSponsor"/> 
     </xsl:apply-templates> 
    </xsl:template> 
</xsl:stylesheet> 

輸出：

<root> 
    <amendment> 
     <id>1</id> 
     <text>some text</text> 
    </amendment> 
    <amendment> 
     <sectionid>A</sectionid> 
     <sponsor>jon</sponsor> 
     <sponsor>peter</sponsor> 
     <id>8</id> 
     <text>some text</text> 
    </amendment> 
    <amendment> 
     <sectionid>B</sectionid> 
     <sponsor>matt</sponsor> 
     <sponsor>ben</sponsor> 
     <id>5</id> 
     <text>some text</text> 
    </amendment> 
    <amendment> 
     <sectionid>B</sectionid> 
     <sponsor>matt</sponsor> 
     <sponsor>ben</sponsor> 
     <id>4</id> 
     <text>some text</text> 
    </amendment> 
    <amendment> 
     <sectionid>B</sectionid> 
     <sponsor>max</sponsor> 
     <id>6</id> 
     <text>some text</text> 
    </amendment> 
    <amendment> 
     <sectionid>B</sectionid> 
     <sponsor>max</sponsor> 
     <id>7</id> 
     <text>some text</text> 
    </amendment> 
</root> 

注意：從以前的答案的性差異是默認的空節點集表達式這些規則中的參數是必要的。