我正在嘗試使用fullCalendar和MySQL創建MySQL支持的事件接口。我試圖操作fullCalendar文檔中的示例,併成功從我的數據庫創建了一個事件源。fullCalendar事件發佈到MySQL的方法
我現在試圖創建一個eventDrop
調用,它將一個事件ID,標題和開始時間發送到數據庫。我使用的代碼從以前的question創建eventDrop
呼叫,這裏是JavaScript整個卡倫德頁:
$(document).ready(function() {
/* initialize the external events
-----------------------------------------------------------------*/
$('#external-events div.external-event').each(function() {
// create an Event Object (http://arshaw.com/fullcalendar/docs/event_data/Event_Object/)
// it doesn't need to have a start or end
var eventObject = {
title: $.trim($(this).text()) // use the element's text as the event title
};
// store the Event Object in the DOM element so we can get to it later
$(this).data('eventObject', eventObject);
// make the event draggable using jQuery UI
$(this).draggable({
zIndex: 999,
revert: true, // will cause the event to go back to its
revertDuration: 0 // original position after the drag
});
});
/* initialize the calendar
-----------------------------------------------------------------*/
$('#calendar').fullCalendar({
header: {
left: 'prev,next today',
center: 'title',
right: 'month,agendaWeek,agendaDay'
},
editable: true,
droppable: true, // this allows things to be dropped onto the calendar !!!
drop: function(date, allDay) { // this function is called when something is dropped
// retrieve the dropped element's stored Event Object
var originalEventObject = $(this).data('eventObject');
// we need to copy it, so that multiple events don't have a reference to the same object
var copiedEventObject = $.extend({}, originalEventObject);
// assign it the date that was reported
copiedEventObject.start = date;
copiedEventObject.allDay = allDay;
// render the event on the calendar
// the last `true` argument determines if the event "sticks" (http://arshaw.com/fullcalendar/docs/event_rendering/renderEvent/)
$('#calendar').fullCalendar('renderEvent', copiedEventObject, true);
// if so, remove the element from the "Draggable Events" list
$(this).remove();
},
// events from mysql database
events: "/json-events.php",
// submit to database
eventDrop: function(calEvent, jsEvent, view) {
var method = 'POST';
var path = 'submit.php';
var params = new Array();
params['id'] = calEvent.id;
params['start'] = calEvent.start;
params['end'] = calEvent.end;
params['title'] = calEvent.title;
post_to_url(path, params, method);
}
});
});
的PHP文件我希望會收到POST數據,並將其與最終插入到數據庫時間等於開始時間加上15分鐘(下面答案後編):
<?php
mysql_connect("") or die(mysql_error());
mysql_select_db("") or die(mysql_error());
$id = $_POST["id"];
$title = $_POST["title"];
$start = $_POST["start"];
$end = date(Y-m-d T H:i:s , strtotime($start)+900);
$query = "INSERT INTO `events` VALUES (`$id`, `$title`, `$start`, `$end`, ``)";
mysql_query($query);
print $query;
?>
數據庫沒有接收到所述的事件數據。
感謝您的回答。我想我理解並開始用直接值測試我的提交文件,並且沒有運氣檢查數據庫。我已經將php文件更改爲:'$ id = $ _POST [「id」]; $ title = $ _POST [「title」]; $ start = $ _POST [「start」]; $結束日期=(Y-M-dŤH:I:S,的strtotime($開始)900); $查詢= 「INSERT INTO'events' VALUES('$ id','$ title','$ start','$ end','')」; mysql_query($ query); 打印$查詢'直接傳遞變量時,通過url我得到一個內部服務器錯誤? – SlartyBartfast