將圖像上傳到遠程服務器，iPhone

Question

我想從圖書館或相機拍攝圖像並將其上傳到遠程服務器，然後我可以在其中爲每個上傳的圖像取回一個URL。

我希望從頭開始。我正在尋找從何處開始的一些幫助。

我需要這樣做最簡單的方式，PHP和MySQL。 我應該從哪裏開始？

另外，我寧願不使用任何第三方。

只是簡單的，

我如何DB連接， 插入 讀 完成！

讓我知道。

Answer 1

哇，我ROCK！

和這個傢伙。 http://iphone.zcentric.com/2008/08/29/post-a-uiimage-to-the-web/

繼承人什麼我實現

UIImage *myImage = [UIImage imageNamed:@"foo.png"]; 
NSData *imageData = UIImagePNGRepresentation(myImage); 
// setting up the URL to post to 
NSString *urlString = @"myurl/insert.php"; 

// setting up the request object now 
NSMutableURLRequest *request = [[[NSMutableURLRequest alloc] init] autorelease]; 
[request setURL:[NSURL URLWithString:urlString]]; 
[request setHTTPMethod:@"POST"]; 

NSString *boundary = [NSString stringWithString:@"---------------------------14737809831466499882746641449"]; 
NSString *contentType = [NSString stringWithFormat:@"multipart/form-data; boundary=%@",boundary]; 
[request addValue:contentType forHTTPHeaderField: @"Content-Type"]; 

/* 
now lets create the body of the post 
*/ 
NSMutableData *body = [NSMutableData data]; 
[body appendData:[[NSString stringWithFormat:@"\r\n--%@\r\n",boundary] dataUsingEncoding:NSUTF8StringEncoding]]; 
[body appendData:[[NSString stringWithString:@"Content-Disposition: form-data; name=\"userfile\"; filename=\"ipodfile.jpg\"\r\n"] dataUsingEncoding:NSUTF8StringEncoding]]; 
[body appendData:[[NSString stringWithString:@"Content-Type: application/octet-stream\r\n\r\n"] dataUsingEncoding:NSUTF8StringEncoding]]; 
[body appendData:[NSData dataWithData:imageData]]; 
[body appendData:[[NSString stringWithFormat:@"\r\n--%@--\r\n",boundary] dataUsingEncoding:NSUTF8StringEncoding]]; 
// setting the body of the post to the reqeust 
[request setHTTPBody:body]; 

// now lets make the connection to the web 
NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil]; 
NSString *returnString = [[NSString alloc] initWithData:returnData encoding:NSUTF8StringEncoding]; 

NSLog(returnString); 

至於它看起來像PHP。

<?php 
     $uploaddir = './uploads/'; 
    $file = basename($_FILES['userfile']['name']); 
    $uploadfile = $uploaddir . $file; 

    if (move_uploaded_file($_FILES['userfile']['tmp_name'], $uploadfile)) { 
     echo "myurl/uploads/{$file}"; 
     } 
?> 

老闆!!! @lessfame