當通過ajax發送複選框值到php時，調用結果失敗php

Question

我想通過ajax將7個jquery複選框的值發送到php。我正在嘗試將值放入一個數組，並在ajax中序列化數組。最終，我想使用選中複選框的值，因爲條件是MySQL WHERE子句。當我嘗試在php中使用結果時，我的代碼失敗，並且該頁面中的表不會顯示。但是，如果我在該php頁面中註釋$ _POST行，我的表格會顯示。當在瀏覽器中檢查代碼時，我會在表中顯示500（內部服務器錯誤）。我也有AJAX顯示這是如下的錯誤結果：

[對象的對象]

CODE：

我的HTML代碼：

<label for="prestage_select">Prestage</label> 
    <input type="checkbox" name="revenue_checkboxes[]" id="prestage_select" value="Prestage"> 


    <label for="validation_select">Validation</label> 
    <input type="checkbox" name="revenue_checkboxes[]" id="validation_select" value="Validation"> 


    <label for="scheduling_select">Scheduling</label> 
    <input type="checkbox" name="revenue_checkboxes[]" id="scheduling_select" value="Scheduling"> 


    <label for="production_select">Production</label> 
    <input type="checkbox" name="revenue_checkboxes[]" id="production_select" value="Production"> 


    <label for="needsBOL_select">Needs BOL</label> 
    <input type="checkbox" name="revenue_checkboxes[]" id="needsBOL_select" value="Needs BOL"> 


    <label for="shpAcct2Close_select">Shipped: Account to Close</label> 
    <input type="checkbox" name="revenue_checkboxes[]" id="shpAcct2Close_select" value="Shipped: Acctg. To Close Out"> 


    <label for="movedToComplete_select">Moved to Complete for Selected Period</label> 
    <input type="checkbox" name="revenue_checkboxes[]" id="movedToComplete_select" value="Complete"> 

我的Ajax代碼：

j("#create_submit").click(function(){ 

      //Send Revenue Status Values to php using ajax.  
       j.ajax({ 
        method: 'POST', 
        url: 'revenue_report.php', 
        data: j('[name="revenue_checkboxes[]"]').serialize(), 
        success: function(response) { 
          j('#fieldset_ReportDiv').html(response); 
          } 
        }); 


     //send Revenue Date values to php using ajax. 
        var revenuefrom = j('#revenuefrom').val(); 
        var revenueto = j('#revenueto').val(); 
        j.ajax ({ 
         method: 'POST', 
         url: "revenue_report.php", 
         data: { revenuefromtext: revenuefrom, revenuetotext: revenueto }, 
         success: function(response) { 
          j('#fieldset_ReportDiv').html(response); 
          } 
        }); 

我的PHP代碼：

<?php 

    include('inc.php'); 


    //Get date range. 

    $revenuefromajax=$_POST['revenuefromtext']; 
    $revenuetoajax=$_POST['revenuetotext']; 

    $revenuefromstring = strtotime($revenuefromajax); 
    $revenuetostring = strtotime($revenuetoajax); 

    $revenuefrom=date("Y-m-d", $revenuefromstring); 
    $revenueto=date("Y-m-d", $revenuetostring); 


    //Get selected Status Values. 

    $revenuecheckboxes=$_POST('revenue_checkboxes'); //the page loads properly when this line is commented out. As soon as I remove the comment, it breaks. 





    //connect to the database 
    $conn = new mysqli($servername, $username, $password, $dbname); 

    // Check connection 
    if(mysqli_connect_errno()) { 
     printf('Could not connect: ' . mysqli_connect_error()); 
     exit(); 
    } 

    //echo 'MySQL Connected successfully.'."<BR>"; 


    $conn->select_db("some database name"); /////Database name has been changed for security reasons///////// 

    if(! $conn->select_db('some database name')) { 

     echo 'Could not select database. '."<BR>"; 
    } 

    // echo 'Successfully selected database. '."<BR>"; 

    //Select Data and Display it in a table. 


    $sql = "SELECT invoices.id, invoices.orderdate, invoices.stagestatus, FORMAT(TRIM(LEADING '$' FROM invoices.totalprice), 2) AS totalprice, clients.company, lineitems.invoiceid, FORMAT((lineitems.width * lineitems.height) /144, 2) AS sqft, lineitems.quantity AS qty, FORMAT((invoices.totalprice/((lineitems.width * lineitems.height) /144)), 2) as avgsqftrevenue, FORMAT((TRIM(LEADING '$' FROM invoices.totalprice)/lineitems.quantity), 2) AS avgunitrevenue 
    FROM clients 
    INNER JOIN invoices ON clients.id = invoices.clientid 
    INNER JOIN lineitems ON invoices.id = lineitems.invoiceid 
    WHERE invoices.orderdate BETWEEN '".$revenuefrom."' AND '".$revenueto."' 
    ORDER BY invoices.id DESC"; 


    $result = $conn->query($sql); 


    echo "<table id='revenueReportA' align='center' class='report_DT'> 
    <tr> 

    <th>Customer</th> 
    <th>SG</th> 
    <th>Revenue</th> 
    <th>SQ FT</th> 
    <th>AVG Revenue Per SQ FT</th> 
    <th>Number of Units</th> 
    <th>AVG Revenue Per Unit</th> 
    </tr>"; 


    if ($result = $conn->query($sql)) { 

     // fetch associative array 
     while ($row = $result->fetch_assoc()) { 


     echo "<tr>"; 
     echo "<td>" . $row['company'] . "</td>"; 
     echo "<td>" . $row['id'] . "</td>"; 
     echo "<td>" ."$". $row['totalprice'] . "</td>"; 
     echo "<td>" . $row['sqft'] ."&nbsp;&nbsp;". "ft<sup>2</sup>". "</td>"; 
     echo "<td>" ."$". $row['avgsqftrevenue'] . "</td>"; 
     echo "<td>" . $row['qty'] . "</td>"; 
     echo "<td>" ."$". $row['avgunitrevenue'] . "</td>"; 
     echo "</tr>"; 
     } 

      echo "</table>"; 

     //////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////// 



    //Free the result variable. 
    $result->free(); 

    } 


    //Close the Database connection. 
    $conn->close(); 


    ?> 

我已經嘗試了幾種不同的建議將值發送到php，但ajax保持失敗。

注意：我包括其他ajax調用revenueto和revenuefrom日期。這個調用是成功的，只要複選框ajax的數據被註釋掉，我的表就可以基於這些日期正確顯示。

注2：道歉，因爲我是新來的ajax。

謝謝！

Answer 1

那$_POST是不正確的。序列化的是輸入的名稱/值。在輸入名稱的[]將被自動地拾起$_POST爲數組的關鍵revenue_checkboxes

嘗試

$revenuecheckboxes = $_POST['revenue_checkboxes'];// should be an array of the checked checkboxes 

Answer 2

你獲得陣列$revenuecheckboxes=$_POST('[name="revenue_checkboxes[]"]');的方法是無效的（不要去與這裏的JavaScript的方式; D）它應該爲$revenuecheckboxes=$_POST['revenue_checkboxes'];

PHP會自動發現它的數組，並將初始化'收支檢查框'與其陣列值