一旦進入狀態，怎樣才能擺脫困境？

Question

想象一下，我有這樣的事情。 x每秒計算一次，並且每秒都有不同的值。基於x的值，我想要做的事，以不同的x

if 10 > x > 0: 
    print "It's temporary" 
    do_something(x) 
elif x < 0: 
    print "It gets activated but stay activated" 
    do_something_else(x) 

如果x的首要條件，它不進入條件的兩個，但我感興趣的是，一旦X去第二個條件，即使x返回並變爲正數，它也不會進入第一個條件，但會停留在第二個條件中。

是否有任何刻板算法來做這樣的事情？

Answer 1

基於在評論你的澄清，它出現在下面的遞歸功能可用於你的目的

def do_something(x, stayActivated = False): 
    if not stayActivated and (10 > x > 0): 
     print "It's temporary" 
     # make an adjustment with said external function 
     do_something(x) 
    elif not stayActivated and x < 0: 
     print "It gets activated but stays activated" 
     do_something_else(x, stayActivated = True) 
    elif x < 0: 
     # x has already been activated and other handling can be applied until any final 
     # condition is met 

Answer 2

假設您可以將它適應於x不是靜態值的環境，則類似這樣的情況將會奏效。

while 10 > x > 0: 
    print "It's temporary" 
    do_something(x) 
while True: # or something that has a chance of being false 
    if x < 0: 
     print "It gets activated but stay activated" 
     do_something_else(x)