我已經解決了這個問題,而不是試圖使編譯器解釋值作爲十六進制我只是做一個查找表包含全部256個可能的字節。
unsigned char Table[] = { 0x00, 0x01, 0x02, 0x03, 0x04, 0x05, 0x06, 0x07, 0x08, 0x09, 0x0A, 0x0B, 0x0C, 0x0D, 0x0E, 0x0F, 0x10, 0x11, 0x12, 0x13, 0x14, 0x15, 0x16, 0x17, 0x18, 0x19, 0x1A, 0x1B, 0x1C, 0x1D, 0x1E, 0x1F, 0x20, 0x21, 0x22, 0x23, 0x24, 0x25, 0x26, 0x27, 0x28, 0x29, 0x2A, 0x2B, 0x2C, 0x2D, 0x2E, 0x2F, 0x30, 0x31, 0x32, 0x33, 0x34, 0x35, 0x36, 0x37, 0x38, 0x39, 0x3A, 0x3B, 0x3C, 0x3D, 0x3E, 0x3F, 0x40, 0x41, 0x42, 0x43, 0x44, 0x45, 0x46, 0x47, 0x48, 0x49, 0x4A, 0x4B, 0x4C, 0x4D, 0x4E, 0x4F, 0x50, 0x51, 0x52, 0x53, 0x54, 0x55, 0x56, 0x57, 0x58, 0x59, 0x5A, 0x5B, 0x5C, 0x5D, 0x5E, 0x5F, 0x60, 0x61, 0x62, 0x63, 0x64, 0x65, 0x66, 0x67, 0x68, 0x69, 0x6A, 0x6B, 0x6C, 0x6D, 0x6E, 0x6F, 0x70, 0x71, 0x72, 0x73, 0x74, 0x75, 0x76, 0x77, 0x78, 0x79, 0x7A, 0x7B, 0x7C, 0x7D, 0x7E, 0x7F, 0x80, 0x81, 0x82, 0x83, 0x84, 0x85, 0x86, 0x87, 0x88, 0x89, 0x8A, 0x8B, 0x8C, 0x8D, 0x8E, 0x8F, 0x90, 0x91, 0x92, 0x93, 0x94, 0x95, 0x96, 0x97, 0x98, 0x99, 0x9A, 0x9B, 0x9C, 0x9D, 0x9E, 0x9F, 0xA0, 0xA1, 0xA2, 0xA3, 0xA4, 0xA5, 0xA6, 0xA7, 0xA8, 0xA9, 0xAA, 0xAB, 0xAC, 0xAD, 0xAE, 0xAF, 0xB0, 0xB1, 0xB2, 0xB3, 0xB4, 0xB5, 0xB6, 0xB7, 0xB8, 0xB9, 0xBA, 0xBB, 0xBC, 0xBD, 0xBE, 0xBF, 0xC0, 0xC1, 0xC2, 0xC3, 0xC4, 0xC5, 0xC6, 0xC7, 0xC8, 0xC9, 0xCA, 0xCB, 0xCC, 0xCD, 0xCE, 0xCF, 0xD0, 0xD1, 0xD2, 0xD3, 0xD4, 0xD5, 0xD6, 0xD7, 0xD8, 0xD9, 0xDA, 0xDB, 0xDC, 0xDD, 0xDE, 0xDF, 0xE0, 0xE1, 0xE2, 0xE3, 0xE4, 0xE5, 0xE6, 0xE7, 0xE8, 0xE9, 0xEA, 0xEB, 0xEC, 0xED, 0xEE, 0xEF, 0xF0, 0xF1, 0xF2, 0xF3, 0xF4, 0xF5, 0xF6, 0xF7, 0xF8, 0xF9, 0xFA, 0xFB, 0xFC, 0xFD, 0xFE, 0xFF };
int GetIndexNumber(string str){
unsigned long rint = NULL;
unsigned long size = str.size() - 2;
unsigned long fi[sizeof(str)];
unsigned long mul;
for(int i = 0; i != 2; i++){
if(str.at(i+2) == '0') fi[i] = 0;
if(str.at(i+2) == '1') fi[i] = 1;
if(str.at(i+2) == '2') fi[i] = 2;
if(str.at(i+2) == '3') fi[i] = 3;
if(str.at(i+2) == '4') fi[i] = 4;
if(str.at(i+2) == '5') fi[i] = 5;
if(str.at(i+2) == '6') fi[i] = 6;
if(str.at(i+2) == '7') fi[i] = 7;
if(str.at(i+2) == '8') fi[i] = 8;
if(str.at(i+2) == '9') fi[i] = 9;
if(str.at(i+2) == 'A') fi[i] = 10;
if(str.at(i+2) == 'B') fi[i] = 11;
if(str.at(i+2) == 'C') fi[i] = 12;
if(str.at(i+2) == 'D') fi[i] = 13;
if(str.at(i+2) == 'E') fi[i] = 14;
if(str.at(i+2) == 'F') fi[i] = 15;
}
for(int i = 0; i != 2 ; i++){
mul = (1 * pow(16, (double)size-1));
size--;
rint += (mul * fi[i]);
}
return rint;
}
Recv();
string Edat = Recv();
Edat += Recv();
cout<<Edat.c_str()<<endl<<endl;
unsigned char buffer[10000] = "";
for(int i = 0; i <= Edat.size(); i++){
int PlaceHolder = Edat.find_first_of("0x");
if(PlaceHolder <= Edat.size() && PlaceHolder > 0){
string tmpstr = Edat.substr(PlaceHolder, 4);
int TableNumber = GetIndexNumber(tmpstr);
buffer[i] = Table[TableNumber];
}
Edat.replace(PlaceHolder, 4, "");
}
std::ofstream put("Eprog.exe", ios::binary);
put.write((char *)buffer, sizeof(buffer));
put.close();
return 0;
}
我錯了或ios :: hex是位圖,運算符是std :: hex? – 2010-11-05 21:01:41
他可能希望ios :: binary而不是ios :: hex。但這不是唯一的問題。 – 2010-11-05 21:04:55