在紅寶石中替換多維數組中的元素

Question

我有一個紅寶石多維數組，如下所示：[[a, b, c], [d, e, f], [g, h, i]]我想用這個函數.gsub!(/\s+/, "")刪除每個數組中每個第二個對象的空格。所以它基本上是這樣做的：[[a, b.gsub!(/\s+/, ""), c], [d, e.gsub!(/\s+/, ""), f], [g, h.gsub!(/\s+/, ""), i]]

我有點困惑，我該怎麼做？

Answer 1

arr = [[a, b, c], [d, e, f], [g, h, i]] 

就地：

arr.each { |a| a[1].delete! ' ' } 

永恆：

arr.dup.each { |a| a[1].delete! ' ' } 

Answer 2

arr = [[a, b, c], [d, e, f], [g, h, i]] 

arr.map! do |el| 
    el[1].gsub!(/\s+/, "") 
    el 
end 

注意：這將改變你的原始數組，這可能是你不想要的東西。

Answer 3

arr = [["Now is", "the time for", "all"], 
     ["good", "people to come", "to", "the"], 
     ["aid of", "their bowling", "team"]] 

arr.map { |a,b,*c| [a, b.delete(' '), *c] } 
    #=> [["Now is", "thetimefor", "all"], 
    # ["good", "peopletocome", "to", "the"], 
    # ["aid of", "theirbowling", "team"]] 

變異arr：

arr.map! { |a,b,*c| [a, b.delete(' '), *c] }