打印字母順序列表

Question

我有以下代碼，它是一個地址簿（字典列表）和一個列表。這個想法是按照列表的順序打印字典中的項目（因爲dicts弄亂了所有內容的順序）。當我運行這段代碼時，它會拋出一個異常（如下所示）。我不確定我做錯了什麼，因爲我嘗試了很多不同的變化，我一直回到這個奇怪的原因，爲什麼它不工作。

請幫忙？

addressBook = [ 
    { 
    'Nickname': 'Jimmy', 
    'Name': 'James Roberts', 
    'Address': '2/50 Robe Street', 
    'Phone': '0273503342' 
    }, 
    { 
    'Nickname': 'Bob', 
    'Name': 'Robert', 
    'Address': '1 Vivan Street', 
    'Phone': '067578930' 
    } 
] 

addressFields = ['Nickname', 'Name', 'Address', 'Phone'] 

def listAll(addressBook, addressFields): 
    for i in addressBook: 
     for key in addressFields: 
      print("{0} {1}".format(key, addressBook[i][key])) 

    print("{0} {1}".format(key, addressBook[i][key])) 


TypeError: list indices must be integers, not dict 

Answer 1

首先，你'James Roberts後失蹤的addressBook字面'。其次，問題在於您正在執行addressBook[i][key]而不是i[key]。 i已經引用了包含在addressBook中的字典，所以你的代碼試圖使用list的元素作爲自己的索引。

def listAll(addressBook, addressFields): 
    for i in addressBook: 
     for key in addressFields: 
      print('{} {}'.format(key, i[key])) 

Python 3的友好單行：

def listAll(addressBook, addressFields): 
    print(*('{} {}'.format(j, i[j]) for i in addressBook for j in addressFields), sep='\n') 

Answer 2

在發佈這個問題後，我找到了答案。

我將addressBook for loop轉換爲一個範圍（len（addressBook）），它工作。

for i in range(len(addressBook)): 

Answer 3

#!/usr/bin/python 

addressBook = [{'Nickname': 'Jimmy', 'Name': 'James Roberts', 'Address': '2/50 Robe Street', 'Phone': '0273503342'},{'Nickname': 'Bob', 'Name': 'Robert', 'Address': '1 Vivan Street', 'Phone': '067578930'}] 

addressFields = ['Nickname', 'Name', 'Address', 'Phone'] 

def listAll(addressBook, addressFields): 
    for i in addressBook: 
    for val in addressFields: 
     print("{0} {1}".format(val, i[val])) 

listAll(addressBook, addressFields) 

Answer 4

可選地在一行：

print('\n'.join(element for element in [j+" "+ i[j] for i in addressBook for j in addressFields] 
))