如何在查詢中調用字符串變體？

public void savedate(String tblname,String time) 
    { 
     ContentValues values = new ContentValues(); 
     values.put(COLUMN_TABLE_NAME, tblname); 
     values.put(COLUMN_TIME, time); 
     String count ="select "+COLUMN_TABLE_NAME+" from "+TABLE_NAME+" where "+COLUMN_TABLE_NAME+ tblname; 
     Cursor mcursor = db.rawQuery(count, null); 
     if(mcursor.getCount()>0) 
     { 
      long s = db.update(TABLE_NAME, values, COLUMN_TIME + "=? ", new String[]{time}); 
      if (s != -1) 

       Toast.makeText(context, "updated, row id: " + s, Toast.LENGTH_SHORT).show(); 
      else 
       Toast.makeText(context, "no change", Toast.LENGTH_SHORT).show(); 
     } 
     else 
     { 
      long s=db.insert(TABLE_NAME, null, values); 
      if(s != -1) 
       Toast.makeText(context, "inserted, row id: " + s, Toast.LENGTH_SHORT).show(); 
      else 
       Toast.makeText(context, "no_change", Toast.LENGTH_SHORT).show(); 

     } 


    }

這是我的代碼，這使一個錯誤：如何在查詢中調用字符串變體？

06-20 11:09:52.258 2001-2348/com.example.mytest.syncapp E/SQLiteLog﹕ (1) no such column: college1 
06-20 11:09:52.260 2001-2348/com.example.mytest.syncapp E/Webservice 1﹕ android.database.sqlite.SQLiteException: no such column: college1 (code 1): , while compiling: select table_name from datesync where table_name= college1

SQLite表結構：
sqlite table structure

來源

2016-06-20 Nithin Jose

'tblName'的值是什麼？ –

COLUMN_TABLE_NAME && TABLE_NAME的值是什麼？ –

tblname refres作爲table_name的字段值，這裏是college1 ;. COLUMN_TABLE_NAME && TABLE_NAME的值是college1和相應的日期 –

最後執行該代碼......

字符串count =「select」+ COLUMN_TABLE_NAME +「from」+ TABLE_NAME +「where」+ COLUMN_TABLE_NAME +「='」+ tblname +「'」;

Cursor mcursor = db.rawQuery(count, null);

來源

2016-06-20 10:20:46

如何在查詢中調用字符串變體？

回答

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