2013-04-22 132 views

回答

2

LongWritable實現可比所以使用compareTo方法:

if (lw1.compareTo(lw2) == 0) { 
    // lw1 has same value as lw2 
} 
+0

它工作得很好...日Thnx – Divyendra 2013-04-23 18:29:07