從文本文件（Python）的

Question

char1= "P" 
length=5 
f = open("wl.txt", 'r') 

for line in f: 
if len(line)==length and line.rstrip() == char1: 
    z=Counter(line) 
    print z 

讀取線specfic角色，我想只輸出線，其中長度= 5和包含字符p.So遠

f = open("wl.txt", 'r') 
    for line in f: 
    if len(line)==length :#This one only works with the length 
     z=Counter(line) 
     print z 

任何猜測別人？

Answer 1

您的問題是：

if len(line)==length and line.rstrip() == char1: 

如果行是5個字符長，然後除去尾隨空格之後，你再對比看看它是否等於長度爲1的串......「ABCDE '永遠不會等於'p'，例如，如果你的行包含'p'，因爲它不是5個字符，你的支票將永遠不會運行...

我不確定你想要做什麼Counter

更正後的代碼是：

# note in capitals to indicate 'constants' 
LENGTH = 5 
CHAR = 'p' 

with open('wl.txt') as fin: 
    for line in fin: 
     # Check length *after* any trailing whitespace has been removed 
     # and that CHAR appears anywhere **in** the line 
     if len(line.rstrip()) == LENGTH and CHAR in line: 
      print 'match:', line